Taylor series (function) [closed]
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Please help me develop this function $f(x)= frac{arccos(x)}{sin(x)+cos(x)}$ near $0$, order $o(x^4)$. I started expanding it with derivatives, but the second one is really long and i stopped.
taylor-expansion
edited Jan 13 at 20:03
user
6,62511031
asked Jan 13 at 18:04
DontorDontor
11
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closed as off-topic by Namaste, Xander Henderson, mrtaurho, Holo, user91500 Jan 15 at 6:39
This question appears to be off-topic. The users who voted to close gave this specific reason:
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$begingroup$
Please help me develop this function $f(x)= frac{arccos(x)}{sin(x)+cos(x)}$ near $0$, order $o(x^4)$. I started expanding it with derivatives, but the second one is really long and i stopped.
taylor-expansion
edited Jan 13 at 20:03
user
6,62511031
asked Jan 13 at 18:04
DontorDontor
11
$endgroup$
closed as off-topic by Namaste, Xander Henderson, mrtaurho, Holo, user91500 Jan 15 at 6:39
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Namaste, Xander Henderson, mrtaurho, Holo, user91500
If this question can be reworded to fit the rules in the help center, please edit the question.
add a comment |
$begingroup$
Please help me develop this function $f(x)= frac{arccos(x)}{sin(x)+cos(x)}$ near $0$, order $o(x^4)$. I started expanding it with derivatives, but the second one is really long and i stopped.
taylor-expansion
edited Jan 13 at 20:03
user
6,62511031
asked Jan 13 at 18:04
DontorDontor
11
$endgroup$
Please help me develop this function $f(x)= frac{arccos(x)}{sin(x)+cos(x)}$ near $0$, order $o(x^4)$. I started expanding it with derivatives, but the second one is really long and i stopped.
taylor-expansion
taylor-expansion
edited Jan 13 at 20:03
user
6,62511031
asked Jan 13 at 18:04
DontorDontor
11
edited Jan 13 at 20:03
user
6,62511031
asked Jan 13 at 18:04
DontorDontor
11
edited Jan 13 at 20:03
user
6,62511031
edited Jan 13 at 20:03
user
6,62511031
edited Jan 13 at 20:03
user
6,62511031
6,62511031
asked Jan 13 at 18:04
DontorDontor
11
asked Jan 13 at 18:04
DontorDontor
11
asked Jan 13 at 18:04
DontorDontor
11
11
closed as off-topic by Namaste, Xander Henderson, mrtaurho, Holo, user91500 Jan 15 at 6:39
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Namaste, Xander Henderson, mrtaurho, Holo, user91500
If this question can be reworded to fit the rules in the help center, please edit the question.
closed as off-topic by Namaste, Xander Henderson, mrtaurho, Holo, user91500 Jan 15 at 6:39
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Namaste, Xander Henderson, mrtaurho, Holo, user91500
If this question can be reworded to fit the rules in the help center, please edit the question.
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1 Answer
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Hint: Solve the equation$$fracpi2-x-frac{x^3}6=left(1+x-frac{x^2}2-frac{x^3}6+frac{x^4}{24}right)left(a_0+a_1x+a_2x^2+a_3x^3+a_4x^4right).$$
answered Jan 13 at 18:12
José Carlos SantosJosé Carlos Santos
175k24134243
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
Hint: Solve the equation$$fracpi2-x-frac{x^3}6=left(1+x-frac{x^2}2-frac{x^3}6+frac{x^4}{24}right)left(a_0+a_1x+a_2x^2+a_3x^3+a_4x^4right).$$
answered Jan 13 at 18:12
José Carlos SantosJosé Carlos Santos
175k24134243
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add a comment |
$begingroup$
Hint: Solve the equation$$fracpi2-x-frac{x^3}6=left(1+x-frac{x^2}2-frac{x^3}6+frac{x^4}{24}right)left(a_0+a_1x+a_2x^2+a_3x^3+a_4x^4right).$$
answered Jan 13 at 18:12
José Carlos SantosJosé Carlos Santos
175k24134243
$endgroup$
add a comment |
$begingroup$
Hint: Solve the equation$$fracpi2-x-frac{x^3}6=left(1+x-frac{x^2}2-frac{x^3}6+frac{x^4}{24}right)left(a_0+a_1x+a_2x^2+a_3x^3+a_4x^4right).$$
answered Jan 13 at 18:12
José Carlos SantosJosé Carlos Santos
175k24134243
$endgroup$
Hint: Solve the equation$$fracpi2-x-frac{x^3}6=left(1+x-frac{x^2}2-frac{x^3}6+frac{x^4}{24}right)left(a_0+a_1x+a_2x^2+a_3x^3+a_4x^4right).$$
answered Jan 13 at 18:12
José Carlos SantosJosé Carlos Santos
175k24134243
answered Jan 13 at 18:12
José Carlos SantosJosé Carlos Santos
175k24134243
answered Jan 13 at 18:12
José Carlos SantosJosé Carlos Santos
175k24134243
answered Jan 13 at 18:12
José Carlos SantosJosé Carlos Santos
175k24134243
175k24134243
add a comment |
add a comment |
