How many integer solutions are there to the equation $x_1+x_2+x_3+2x_4+x_5=72$?











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If the question given is to find the number of integer solutions to the equation $x_1+x_2+x_3+x_4+x_5=72$ where $x_1ge2, x_2,x_3ge1, x_4,x_5ge0$



I know that the solution would be:



$(x_1-2)+(x_2-1)+(x_3-1)+(x_4)+(x_5)=72$



So, $x_1+x_2+x_3+x_4+x_5=76$



And the number of integer solutions would be ${76+5-1 choose 76}$



But how would I find the answer if the equation given is $x_1+x_2+x_3+2x_4+x_5=72$ with same restrictions on $x_i$?










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    If the question given is to find the number of integer solutions to the equation $x_1+x_2+x_3+x_4+x_5=72$ where $x_1ge2, x_2,x_3ge1, x_4,x_5ge0$



    I know that the solution would be:



    $(x_1-2)+(x_2-1)+(x_3-1)+(x_4)+(x_5)=72$



    So, $x_1+x_2+x_3+x_4+x_5=76$



    And the number of integer solutions would be ${76+5-1 choose 76}$



    But how would I find the answer if the equation given is $x_1+x_2+x_3+2x_4+x_5=72$ with same restrictions on $x_i$?










    share|cite|improve this question
























      up vote
      -1
      down vote

      favorite









      up vote
      -1
      down vote

      favorite











      If the question given is to find the number of integer solutions to the equation $x_1+x_2+x_3+x_4+x_5=72$ where $x_1ge2, x_2,x_3ge1, x_4,x_5ge0$



      I know that the solution would be:



      $(x_1-2)+(x_2-1)+(x_3-1)+(x_4)+(x_5)=72$



      So, $x_1+x_2+x_3+x_4+x_5=76$



      And the number of integer solutions would be ${76+5-1 choose 76}$



      But how would I find the answer if the equation given is $x_1+x_2+x_3+2x_4+x_5=72$ with same restrictions on $x_i$?










      share|cite|improve this question













      If the question given is to find the number of integer solutions to the equation $x_1+x_2+x_3+x_4+x_5=72$ where $x_1ge2, x_2,x_3ge1, x_4,x_5ge0$



      I know that the solution would be:



      $(x_1-2)+(x_2-1)+(x_3-1)+(x_4)+(x_5)=72$



      So, $x_1+x_2+x_3+x_4+x_5=76$



      And the number of integer solutions would be ${76+5-1 choose 76}$



      But how would I find the answer if the equation given is $x_1+x_2+x_3+2x_4+x_5=72$ with same restrictions on $x_i$?







      combinatorics discrete-mathematics






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      asked Dec 3 at 4:04









      user394222

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          One simple approach would be to assume $x_4=k$ and solve the problem for $x_1+x_2+x_3+x_5=72-2k$ and sum over all $k$.



          A more general approach would be to construct ordinary generating functions for each variable in question and find the coefficient of $x^{72}$ in their common generating function.






          share|cite|improve this answer





















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            1 Answer
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            up vote
            1
            down vote













            One simple approach would be to assume $x_4=k$ and solve the problem for $x_1+x_2+x_3+x_5=72-2k$ and sum over all $k$.



            A more general approach would be to construct ordinary generating functions for each variable in question and find the coefficient of $x^{72}$ in their common generating function.






            share|cite|improve this answer

























              up vote
              1
              down vote













              One simple approach would be to assume $x_4=k$ and solve the problem for $x_1+x_2+x_3+x_5=72-2k$ and sum over all $k$.



              A more general approach would be to construct ordinary generating functions for each variable in question and find the coefficient of $x^{72}$ in their common generating function.






              share|cite|improve this answer























                up vote
                1
                down vote










                up vote
                1
                down vote









                One simple approach would be to assume $x_4=k$ and solve the problem for $x_1+x_2+x_3+x_5=72-2k$ and sum over all $k$.



                A more general approach would be to construct ordinary generating functions for each variable in question and find the coefficient of $x^{72}$ in their common generating function.






                share|cite|improve this answer












                One simple approach would be to assume $x_4=k$ and solve the problem for $x_1+x_2+x_3+x_5=72-2k$ and sum over all $k$.



                A more general approach would be to construct ordinary generating functions for each variable in question and find the coefficient of $x^{72}$ in their common generating function.







                share|cite|improve this answer












                share|cite|improve this answer



                share|cite|improve this answer










                answered Dec 3 at 4:11









                gt6989b

                32.6k22351




                32.6k22351






























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