What's the null space of [111, 000, 000]?
$begingroup$
This is the matrix after RREF:
[ 1 1 1
0 0 0
0 0 0 ]
I can't find the nulll space of this. let $x_1 = -x_2 -x_3$ . let $x_2 = x_2, x_3 = x_3$.
So I think it's
sp([-1, 1, 0], [-1, 0, 1])
But the solution says it is
sp([1, -1, 0], [1, 0, -1])
How did they get that for the solution? (I'm guessing both are correct? since my solution can form the actual solution, and vise-versa?)
matrices
edited Dec 21 '18 at 10:56
dmtri
1,4782521
asked Dec 21 '18 at 10:04
Jay PatelJay Patel
656
$endgroup$
add a comment |
$begingroup$
This is the matrix after RREF:
[ 1 1 1
0 0 0
0 0 0 ]
I can't find the nulll space of this. let $x_1 = -x_2 -x_3$ . let $x_2 = x_2, x_3 = x_3$.
So I think it's
sp([-1, 1, 0], [-1, 0, 1])
But the solution says it is
sp([1, -1, 0], [1, 0, -1])
How did they get that for the solution? (I'm guessing both are correct? since my solution can form the actual solution, and vise-versa?)
matrices
edited Dec 21 '18 at 10:56
dmtri
1,4782521
asked Dec 21 '18 at 10:04
Jay PatelJay Patel
656
$endgroup$
add a comment |
$begingroup$
This is the matrix after RREF:
[ 1 1 1
0 0 0
0 0 0 ]
I can't find the nulll space of this. let $x_1 = -x_2 -x_3$ . let $x_2 = x_2, x_3 = x_3$.
So I think it's
sp([-1, 1, 0], [-1, 0, 1])
But the solution says it is
sp([1, -1, 0], [1, 0, -1])
How did they get that for the solution? (I'm guessing both are correct? since my solution can form the actual solution, and vise-versa?)
matrices
edited Dec 21 '18 at 10:56
dmtri
1,4782521
asked Dec 21 '18 at 10:04
Jay PatelJay Patel
656
$endgroup$
This is the matrix after RREF:
[ 1 1 1
0 0 0
0 0 0 ]
I can't find the nulll space of this. let $x_1 = -x_2 -x_3$ . let $x_2 = x_2, x_3 = x_3$.
So I think it's
sp([-1, 1, 0], [-1, 0, 1])
But the solution says it is
sp([1, -1, 0], [1, 0, -1])
How did they get that for the solution? (I'm guessing both are correct? since my solution can form the actual solution, and vise-versa?)
matrices
matrices
edited Dec 21 '18 at 10:56
dmtri
1,4782521
asked Dec 21 '18 at 10:04
Jay PatelJay Patel
656
edited Dec 21 '18 at 10:56
dmtri
1,4782521
asked Dec 21 '18 at 10:04
Jay PatelJay Patel
656
edited Dec 21 '18 at 10:56
dmtri
1,4782521
edited Dec 21 '18 at 10:56
dmtri
1,4782521
edited Dec 21 '18 at 10:56
dmtri
1,4782521
1,4782521
asked Dec 21 '18 at 10:04
Jay PatelJay Patel
656
asked Dec 21 '18 at 10:04
Jay PatelJay Patel
656
asked Dec 21 '18 at 10:04
Jay PatelJay Patel
656
656
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
$begingroup$
Yes , both are correct . Let $u=(-1,1,0)$ and $v=(-1,0,1)$. Then
$span{u,v}= span{-u,-v}$.
answered Dec 21 '18 at 10:08
FredFred
45.4k1848
$endgroup$
add a comment |
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1 Answer
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1 Answer
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active
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$begingroup$
Yes , both are correct . Let $u=(-1,1,0)$ and $v=(-1,0,1)$. Then
$span{u,v}= span{-u,-v}$.
answered Dec 21 '18 at 10:08
FredFred
45.4k1848
$endgroup$
add a comment |
$begingroup$
Yes , both are correct . Let $u=(-1,1,0)$ and $v=(-1,0,1)$. Then
$span{u,v}= span{-u,-v}$.
answered Dec 21 '18 at 10:08
FredFred
45.4k1848
$endgroup$
add a comment |
$begingroup$
Yes , both are correct . Let $u=(-1,1,0)$ and $v=(-1,0,1)$. Then
$span{u,v}= span{-u,-v}$.
answered Dec 21 '18 at 10:08
FredFred
45.4k1848
$endgroup$
Yes , both are correct . Let $u=(-1,1,0)$ and $v=(-1,0,1)$. Then
$span{u,v}= span{-u,-v}$.
answered Dec 21 '18 at 10:08
FredFred
45.4k1848
answered Dec 21 '18 at 10:08
FredFred
45.4k1848
answered Dec 21 '18 at 10:08
FredFred
45.4k1848
answered Dec 21 '18 at 10:08
FredFred
45.4k1848
45.4k1848
add a comment |
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