Approximate identity for induced algebra












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Let $H$ be a closed subgroup of a locally compact group $G$, and let $A$ be a Banach algebra with an $H$-action $alpha$. Then we can define an induced algebra $mathrm{Ind}A$ with a $G$-action by taking all bounded continuous functions $f:Grightarrow A$ such that $f(sh)=alpha_{h^{-1}}(f(s))$ for all $sin G$ and $hin H$ and such that $sHmapsto||f(s)||$ is in $C_0(G/H)$. It is a Banach algebra under the supremum norm.



If $A$ has a bounded approximate identity, does $mathrm{Ind}A$ have a bounded approximate identity?



Given any $ain A$, I can produce some $finmathrm{Ind}A$ such that the value of $f$ at the identity is close to $a$. But I cannot see how to construct appropriate functions using the approximate identity in $A$ to get one for $mathrm{Ind}A$.



More generally, if $A$ is nondegenerate in the sense that the linear span of products of pairs of elements in $A$ is dense in $A$, is $mathrm{Ind}A$ nondegenerate?










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    $begingroup$


    Let $H$ be a closed subgroup of a locally compact group $G$, and let $A$ be a Banach algebra with an $H$-action $alpha$. Then we can define an induced algebra $mathrm{Ind}A$ with a $G$-action by taking all bounded continuous functions $f:Grightarrow A$ such that $f(sh)=alpha_{h^{-1}}(f(s))$ for all $sin G$ and $hin H$ and such that $sHmapsto||f(s)||$ is in $C_0(G/H)$. It is a Banach algebra under the supremum norm.



    If $A$ has a bounded approximate identity, does $mathrm{Ind}A$ have a bounded approximate identity?



    Given any $ain A$, I can produce some $finmathrm{Ind}A$ such that the value of $f$ at the identity is close to $a$. But I cannot see how to construct appropriate functions using the approximate identity in $A$ to get one for $mathrm{Ind}A$.



    More generally, if $A$ is nondegenerate in the sense that the linear span of products of pairs of elements in $A$ is dense in $A$, is $mathrm{Ind}A$ nondegenerate?










    share|cite|improve this question











    $endgroup$















      0












      0








      0





      $begingroup$


      Let $H$ be a closed subgroup of a locally compact group $G$, and let $A$ be a Banach algebra with an $H$-action $alpha$. Then we can define an induced algebra $mathrm{Ind}A$ with a $G$-action by taking all bounded continuous functions $f:Grightarrow A$ such that $f(sh)=alpha_{h^{-1}}(f(s))$ for all $sin G$ and $hin H$ and such that $sHmapsto||f(s)||$ is in $C_0(G/H)$. It is a Banach algebra under the supremum norm.



      If $A$ has a bounded approximate identity, does $mathrm{Ind}A$ have a bounded approximate identity?



      Given any $ain A$, I can produce some $finmathrm{Ind}A$ such that the value of $f$ at the identity is close to $a$. But I cannot see how to construct appropriate functions using the approximate identity in $A$ to get one for $mathrm{Ind}A$.



      More generally, if $A$ is nondegenerate in the sense that the linear span of products of pairs of elements in $A$ is dense in $A$, is $mathrm{Ind}A$ nondegenerate?










      share|cite|improve this question











      $endgroup$




      Let $H$ be a closed subgroup of a locally compact group $G$, and let $A$ be a Banach algebra with an $H$-action $alpha$. Then we can define an induced algebra $mathrm{Ind}A$ with a $G$-action by taking all bounded continuous functions $f:Grightarrow A$ such that $f(sh)=alpha_{h^{-1}}(f(s))$ for all $sin G$ and $hin H$ and such that $sHmapsto||f(s)||$ is in $C_0(G/H)$. It is a Banach algebra under the supremum norm.



      If $A$ has a bounded approximate identity, does $mathrm{Ind}A$ have a bounded approximate identity?



      Given any $ain A$, I can produce some $finmathrm{Ind}A$ such that the value of $f$ at the identity is close to $a$. But I cannot see how to construct appropriate functions using the approximate identity in $A$ to get one for $mathrm{Ind}A$.



      More generally, if $A$ is nondegenerate in the sense that the linear span of products of pairs of elements in $A$ is dense in $A$, is $mathrm{Ind}A$ nondegenerate?







      banach-algebras






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      share|cite|improve this question













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      edited Jan 6 at 16:19







      cyc

















      asked Jan 6 at 16:11









      cyccyc

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