Optimize visits so the distance of all attendees is nearly equal












0












$begingroup$


We've got 5 persons: A,B,C,D and E.
Each persons has a specific distance to each other person.



For example:
Distance for each person to each other person



Each year, those persons have to meet x times on one of the persons house.
How am I supposed to calculate how ofter everyone has to host a meeting so everyone has approximately the same distance to travel?










share|cite|improve this question









$endgroup$








  • 1




    $begingroup$
    Not necessarily relevant to your question: The distances are inconsistent. For instance A to C is distance $4.3$; C to B is distance $2$. But A to B is $10$. Certainly A could go to C and then on to B for a total distance of $6.3$. I.e., the triangle inequality is violated.
    $endgroup$
    – paw88789
    Jan 4 at 12:42












  • $begingroup$
    You need to solve for $x=1,2$ the rest follow easily enough.
    $endgroup$
    – Macavity
    Jan 7 at 16:38










  • $begingroup$
    @Macavity is it possible for you to give a short explanation?
    $endgroup$
    – C4p741nZ
    Jan 8 at 18:32
















0












$begingroup$


We've got 5 persons: A,B,C,D and E.
Each persons has a specific distance to each other person.



For example:
Distance for each person to each other person



Each year, those persons have to meet x times on one of the persons house.
How am I supposed to calculate how ofter everyone has to host a meeting so everyone has approximately the same distance to travel?










share|cite|improve this question









$endgroup$








  • 1




    $begingroup$
    Not necessarily relevant to your question: The distances are inconsistent. For instance A to C is distance $4.3$; C to B is distance $2$. But A to B is $10$. Certainly A could go to C and then on to B for a total distance of $6.3$. I.e., the triangle inequality is violated.
    $endgroup$
    – paw88789
    Jan 4 at 12:42












  • $begingroup$
    You need to solve for $x=1,2$ the rest follow easily enough.
    $endgroup$
    – Macavity
    Jan 7 at 16:38










  • $begingroup$
    @Macavity is it possible for you to give a short explanation?
    $endgroup$
    – C4p741nZ
    Jan 8 at 18:32














0












0








0





$begingroup$


We've got 5 persons: A,B,C,D and E.
Each persons has a specific distance to each other person.



For example:
Distance for each person to each other person



Each year, those persons have to meet x times on one of the persons house.
How am I supposed to calculate how ofter everyone has to host a meeting so everyone has approximately the same distance to travel?










share|cite|improve this question









$endgroup$




We've got 5 persons: A,B,C,D and E.
Each persons has a specific distance to each other person.



For example:
Distance for each person to each other person



Each year, those persons have to meet x times on one of the persons house.
How am I supposed to calculate how ofter everyone has to host a meeting so everyone has approximately the same distance to travel?







optimization






share|cite|improve this question













share|cite|improve this question











share|cite|improve this question




share|cite|improve this question










asked Jan 4 at 12:31









C4p741nZC4p741nZ

101




101








  • 1




    $begingroup$
    Not necessarily relevant to your question: The distances are inconsistent. For instance A to C is distance $4.3$; C to B is distance $2$. But A to B is $10$. Certainly A could go to C and then on to B for a total distance of $6.3$. I.e., the triangle inequality is violated.
    $endgroup$
    – paw88789
    Jan 4 at 12:42












  • $begingroup$
    You need to solve for $x=1,2$ the rest follow easily enough.
    $endgroup$
    – Macavity
    Jan 7 at 16:38










  • $begingroup$
    @Macavity is it possible for you to give a short explanation?
    $endgroup$
    – C4p741nZ
    Jan 8 at 18:32














  • 1




    $begingroup$
    Not necessarily relevant to your question: The distances are inconsistent. For instance A to C is distance $4.3$; C to B is distance $2$. But A to B is $10$. Certainly A could go to C and then on to B for a total distance of $6.3$. I.e., the triangle inequality is violated.
    $endgroup$
    – paw88789
    Jan 4 at 12:42












  • $begingroup$
    You need to solve for $x=1,2$ the rest follow easily enough.
    $endgroup$
    – Macavity
    Jan 7 at 16:38










  • $begingroup$
    @Macavity is it possible for you to give a short explanation?
    $endgroup$
    – C4p741nZ
    Jan 8 at 18:32








1




1




$begingroup$
Not necessarily relevant to your question: The distances are inconsistent. For instance A to C is distance $4.3$; C to B is distance $2$. But A to B is $10$. Certainly A could go to C and then on to B for a total distance of $6.3$. I.e., the triangle inequality is violated.
$endgroup$
– paw88789
Jan 4 at 12:42






$begingroup$
Not necessarily relevant to your question: The distances are inconsistent. For instance A to C is distance $4.3$; C to B is distance $2$. But A to B is $10$. Certainly A could go to C and then on to B for a total distance of $6.3$. I.e., the triangle inequality is violated.
$endgroup$
– paw88789
Jan 4 at 12:42














$begingroup$
You need to solve for $x=1,2$ the rest follow easily enough.
$endgroup$
– Macavity
Jan 7 at 16:38




$begingroup$
You need to solve for $x=1,2$ the rest follow easily enough.
$endgroup$
– Macavity
Jan 7 at 16:38












$begingroup$
@Macavity is it possible for you to give a short explanation?
$endgroup$
– C4p741nZ
Jan 8 at 18:32




$begingroup$
@Macavity is it possible for you to give a short explanation?
$endgroup$
– C4p741nZ
Jan 8 at 18:32










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