Can these propositions be equivalent?












0












$begingroup$


We all know that:



$P rightarrow Q $



and



$(Not)Q rightarrow (Not)P$



are equivalent.



Is it possible that in specific cases
$P rightarrow Q $
is equivalent with
$Q rightarrow P $
or
$(Not)Q rightarrow P $
or
$P rightarrow (Not)Q $



Can this happen or is that impossible? If it is, how should I attempt to prove it?










share|cite|improve this question









$endgroup$








  • 1




    $begingroup$
    NO; logical equivalence means that "they have the same truth value in every model" (in the case of propostoonal logic : in every truth assignment.
    $endgroup$
    – Mauro ALLEGRANZA
    Jan 13 at 12:28
















0












$begingroup$


We all know that:



$P rightarrow Q $



and



$(Not)Q rightarrow (Not)P$



are equivalent.



Is it possible that in specific cases
$P rightarrow Q $
is equivalent with
$Q rightarrow P $
or
$(Not)Q rightarrow P $
or
$P rightarrow (Not)Q $



Can this happen or is that impossible? If it is, how should I attempt to prove it?










share|cite|improve this question









$endgroup$








  • 1




    $begingroup$
    NO; logical equivalence means that "they have the same truth value in every model" (in the case of propostoonal logic : in every truth assignment.
    $endgroup$
    – Mauro ALLEGRANZA
    Jan 13 at 12:28














0












0








0





$begingroup$


We all know that:



$P rightarrow Q $



and



$(Not)Q rightarrow (Not)P$



are equivalent.



Is it possible that in specific cases
$P rightarrow Q $
is equivalent with
$Q rightarrow P $
or
$(Not)Q rightarrow P $
or
$P rightarrow (Not)Q $



Can this happen or is that impossible? If it is, how should I attempt to prove it?










share|cite|improve this question









$endgroup$




We all know that:



$P rightarrow Q $



and



$(Not)Q rightarrow (Not)P$



are equivalent.



Is it possible that in specific cases
$P rightarrow Q $
is equivalent with
$Q rightarrow P $
or
$(Not)Q rightarrow P $
or
$P rightarrow (Not)Q $



Can this happen or is that impossible? If it is, how should I attempt to prove it?







logic propositional-calculus






share|cite|improve this question













share|cite|improve this question











share|cite|improve this question




share|cite|improve this question










asked Jan 13 at 11:59









Ayoub RossiAyoub Rossi

11110




11110








  • 1




    $begingroup$
    NO; logical equivalence means that "they have the same truth value in every model" (in the case of propostoonal logic : in every truth assignment.
    $endgroup$
    – Mauro ALLEGRANZA
    Jan 13 at 12:28














  • 1




    $begingroup$
    NO; logical equivalence means that "they have the same truth value in every model" (in the case of propostoonal logic : in every truth assignment.
    $endgroup$
    – Mauro ALLEGRANZA
    Jan 13 at 12:28








1




1




$begingroup$
NO; logical equivalence means that "they have the same truth value in every model" (in the case of propostoonal logic : in every truth assignment.
$endgroup$
– Mauro ALLEGRANZA
Jan 13 at 12:28




$begingroup$
NO; logical equivalence means that "they have the same truth value in every model" (in the case of propostoonal logic : in every truth assignment.
$endgroup$
– Mauro ALLEGRANZA
Jan 13 at 12:28










2 Answers
2






active

oldest

votes


















0












$begingroup$

From a truth table $Pto Q$ is equivalent to $Qto P$ iff $P=Q$, to $neg Qto P$ iff $Q$, and to $Ptoneg Q$ iff $Pland Q$. You can easily choose $P,,Q$ to achieve these conditions.






share|cite|improve this answer









$endgroup$





















    0












    $begingroup$

    There is no such thing as two statements being 'sometimes logically equivalent' or 'possibly logically equivalent'. Logical equivalence means always having the same truth-value. If it's not always, it's not equivalence.






    share|cite|improve this answer









    $endgroup$














      Your Answer








      StackExchange.ready(function() {
      var channelOptions = {
      tags: "".split(" "),
      id: "69"
      };
      initTagRenderer("".split(" "), "".split(" "), channelOptions);

      StackExchange.using("externalEditor", function() {
      // Have to fire editor after snippets, if snippets enabled
      if (StackExchange.settings.snippets.snippetsEnabled) {
      StackExchange.using("snippets", function() {
      createEditor();
      });
      }
      else {
      createEditor();
      }
      });

      function createEditor() {
      StackExchange.prepareEditor({
      heartbeatType: 'answer',
      autoActivateHeartbeat: false,
      convertImagesToLinks: true,
      noModals: true,
      showLowRepImageUploadWarning: true,
      reputationToPostImages: 10,
      bindNavPrevention: true,
      postfix: "",
      imageUploader: {
      brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
      contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
      allowUrls: true
      },
      noCode: true, onDemand: true,
      discardSelector: ".discard-answer"
      ,immediatelyShowMarkdownHelp:true
      });


      }
      });














      draft saved

      draft discarded


















      StackExchange.ready(
      function () {
      StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3071939%2fcan-these-propositions-be-equivalent%23new-answer', 'question_page');
      }
      );

      Post as a guest















      Required, but never shown

























      2 Answers
      2






      active

      oldest

      votes








      2 Answers
      2






      active

      oldest

      votes









      active

      oldest

      votes






      active

      oldest

      votes









      0












      $begingroup$

      From a truth table $Pto Q$ is equivalent to $Qto P$ iff $P=Q$, to $neg Qto P$ iff $Q$, and to $Ptoneg Q$ iff $Pland Q$. You can easily choose $P,,Q$ to achieve these conditions.






      share|cite|improve this answer









      $endgroup$


















        0












        $begingroup$

        From a truth table $Pto Q$ is equivalent to $Qto P$ iff $P=Q$, to $neg Qto P$ iff $Q$, and to $Ptoneg Q$ iff $Pland Q$. You can easily choose $P,,Q$ to achieve these conditions.






        share|cite|improve this answer









        $endgroup$
















          0












          0








          0





          $begingroup$

          From a truth table $Pto Q$ is equivalent to $Qto P$ iff $P=Q$, to $neg Qto P$ iff $Q$, and to $Ptoneg Q$ iff $Pland Q$. You can easily choose $P,,Q$ to achieve these conditions.






          share|cite|improve this answer









          $endgroup$



          From a truth table $Pto Q$ is equivalent to $Qto P$ iff $P=Q$, to $neg Qto P$ iff $Q$, and to $Ptoneg Q$ iff $Pland Q$. You can easily choose $P,,Q$ to achieve these conditions.







          share|cite|improve this answer












          share|cite|improve this answer



          share|cite|improve this answer










          answered Jan 13 at 12:15









          J.G.J.G.

          33.6k23252




          33.6k23252























              0












              $begingroup$

              There is no such thing as two statements being 'sometimes logically equivalent' or 'possibly logically equivalent'. Logical equivalence means always having the same truth-value. If it's not always, it's not equivalence.






              share|cite|improve this answer









              $endgroup$


















                0












                $begingroup$

                There is no such thing as two statements being 'sometimes logically equivalent' or 'possibly logically equivalent'. Logical equivalence means always having the same truth-value. If it's not always, it's not equivalence.






                share|cite|improve this answer









                $endgroup$
















                  0












                  0








                  0





                  $begingroup$

                  There is no such thing as two statements being 'sometimes logically equivalent' or 'possibly logically equivalent'. Logical equivalence means always having the same truth-value. If it's not always, it's not equivalence.






                  share|cite|improve this answer









                  $endgroup$



                  There is no such thing as two statements being 'sometimes logically equivalent' or 'possibly logically equivalent'. Logical equivalence means always having the same truth-value. If it's not always, it's not equivalence.







                  share|cite|improve this answer












                  share|cite|improve this answer



                  share|cite|improve this answer










                  answered Jan 13 at 16:02









                  Bram28Bram28

                  64.6k44793




                  64.6k44793






























                      draft saved

                      draft discarded




















































                      Thanks for contributing an answer to Mathematics Stack Exchange!


                      • Please be sure to answer the question. Provide details and share your research!

                      But avoid



                      • Asking for help, clarification, or responding to other answers.

                      • Making statements based on opinion; back them up with references or personal experience.


                      Use MathJax to format equations. MathJax reference.


                      To learn more, see our tips on writing great answers.




                      draft saved


                      draft discarded














                      StackExchange.ready(
                      function () {
                      StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3071939%2fcan-these-propositions-be-equivalent%23new-answer', 'question_page');
                      }
                      );

                      Post as a guest















                      Required, but never shown





















































                      Required, but never shown














                      Required, but never shown












                      Required, but never shown







                      Required, but never shown

































                      Required, but never shown














                      Required, but never shown












                      Required, but never shown







                      Required, but never shown







                      Popular posts from this blog

                      Bressuire

                      Cabo Verde

                      Gyllenstierna