Upper bound for the sup of the first derivative












0












$begingroup$


Given $f : mathbb{R} to mathbb{R}$ which is twice differentiable and that



$M_0 = sup_{x in mathbb{R} } |f(x)|$



$M_1 = sup_{x in mathbb{R} } |f'(x)|$



$M_2 = sup_{x in mathbb{R} } |f''(x)|$



prove that $M_1^2 leq 2 M_0 M_2$ ?



I think a good approach is Taylor series but for what values !










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  • $begingroup$
    math.stackexchange.com/questions/98320/…
    $endgroup$
    – Yanko
    Jan 13 at 11:36
















0












$begingroup$


Given $f : mathbb{R} to mathbb{R}$ which is twice differentiable and that



$M_0 = sup_{x in mathbb{R} } |f(x)|$



$M_1 = sup_{x in mathbb{R} } |f'(x)|$



$M_2 = sup_{x in mathbb{R} } |f''(x)|$



prove that $M_1^2 leq 2 M_0 M_2$ ?



I think a good approach is Taylor series but for what values !










share|cite|improve this question









$endgroup$












  • $begingroup$
    math.stackexchange.com/questions/98320/…
    $endgroup$
    – Yanko
    Jan 13 at 11:36














0












0








0





$begingroup$


Given $f : mathbb{R} to mathbb{R}$ which is twice differentiable and that



$M_0 = sup_{x in mathbb{R} } |f(x)|$



$M_1 = sup_{x in mathbb{R} } |f'(x)|$



$M_2 = sup_{x in mathbb{R} } |f''(x)|$



prove that $M_1^2 leq 2 M_0 M_2$ ?



I think a good approach is Taylor series but for what values !










share|cite|improve this question









$endgroup$




Given $f : mathbb{R} to mathbb{R}$ which is twice differentiable and that



$M_0 = sup_{x in mathbb{R} } |f(x)|$



$M_1 = sup_{x in mathbb{R} } |f'(x)|$



$M_2 = sup_{x in mathbb{R} } |f''(x)|$



prove that $M_1^2 leq 2 M_0 M_2$ ?



I think a good approach is Taylor series but for what values !







real-analysis calculus






share|cite|improve this question













share|cite|improve this question











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share|cite|improve this question










asked Jan 13 at 11:34









AhmadAhmad

2,5771725




2,5771725












  • $begingroup$
    math.stackexchange.com/questions/98320/…
    $endgroup$
    – Yanko
    Jan 13 at 11:36


















  • $begingroup$
    math.stackexchange.com/questions/98320/…
    $endgroup$
    – Yanko
    Jan 13 at 11:36
















$begingroup$
math.stackexchange.com/questions/98320/…
$endgroup$
– Yanko
Jan 13 at 11:36




$begingroup$
math.stackexchange.com/questions/98320/…
$endgroup$
– Yanko
Jan 13 at 11:36










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