Could PATH contain newlines?












3















It is known that a path could contain newlines in any of its components.



Should we conclude then that the environment variable $PATH could contain newlines ?



If so, how to split the $PATH into its elements, similar to (Bourne like):



IFS=':' ; set -f
for var in $PATH
do
echo "<$var>"
done


But if it could be done without changing IFS, even better.










share|improve this question

























  • Note that in the Bourne shell (contrary to POSIX shells), /bin::/usr/bin would be split into /bin and /usr/bin instead of /bin, "" and /usr/bin.

    – Stéphane Chazelas
    Dec 31 '18 at 11:12
















3















It is known that a path could contain newlines in any of its components.



Should we conclude then that the environment variable $PATH could contain newlines ?



If so, how to split the $PATH into its elements, similar to (Bourne like):



IFS=':' ; set -f
for var in $PATH
do
echo "<$var>"
done


But if it could be done without changing IFS, even better.










share|improve this question

























  • Note that in the Bourne shell (contrary to POSIX shells), /bin::/usr/bin would be split into /bin and /usr/bin instead of /bin, "" and /usr/bin.

    – Stéphane Chazelas
    Dec 31 '18 at 11:12














3












3








3








It is known that a path could contain newlines in any of its components.



Should we conclude then that the environment variable $PATH could contain newlines ?



If so, how to split the $PATH into its elements, similar to (Bourne like):



IFS=':' ; set -f
for var in $PATH
do
echo "<$var>"
done


But if it could be done without changing IFS, even better.










share|improve this question
















It is known that a path could contain newlines in any of its components.



Should we conclude then that the environment variable $PATH could contain newlines ?



If so, how to split the $PATH into its elements, similar to (Bourne like):



IFS=':' ; set -f
for var in $PATH
do
echo "<$var>"
done


But if it could be done without changing IFS, even better.







shell path newlines






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Dec 31 '18 at 10:39









ilkkachu

60.1k998171




60.1k998171










asked Dec 31 '18 at 6:34









IsaacIsaac

12k11852




12k11852













  • Note that in the Bourne shell (contrary to POSIX shells), /bin::/usr/bin would be split into /bin and /usr/bin instead of /bin, "" and /usr/bin.

    – Stéphane Chazelas
    Dec 31 '18 at 11:12



















  • Note that in the Bourne shell (contrary to POSIX shells), /bin::/usr/bin would be split into /bin and /usr/bin instead of /bin, "" and /usr/bin.

    – Stéphane Chazelas
    Dec 31 '18 at 11:12

















Note that in the Bourne shell (contrary to POSIX shells), /bin::/usr/bin would be split into /bin and /usr/bin instead of /bin, "" and /usr/bin.

– Stéphane Chazelas
Dec 31 '18 at 11:12





Note that in the Bourne shell (contrary to POSIX shells), /bin::/usr/bin would be split into /bin and /usr/bin instead of /bin, "" and /usr/bin.

– Stéphane Chazelas
Dec 31 '18 at 11:12










2 Answers
2






active

oldest

votes


















3














In POSIX shells, $IFS is a field delimiter, not separator, so a $PATH value like /bin:/usr/bin: would be split into /bin and /usr/bin instead of /bin, /usr/bin and the empty string (meaning the current directory). You need:



IFS=:; set -o noglob
for var in $PATH""; do
printf '<%s>n' "$var"
done


To avoid modifying global settings, you can use a shell with explicit splitting operators like zsh:



for var in "${(s/:/@)PATH}"; do
printf '<%s>n' "$var"
done


Though in that case, zsh already has the $path array tied to $PATH like in csh/tcsh, so:



for var in "$path[@]"; do
printf '<%s>n' "$var"
done


In any case, yes, in theory $PATH like any variable could contain newline characters, the newline character is not special in any way when it comes to file path resolution. I don't expect anyone sensible would put a directory with newline (or wildcards) in their $PATH or name a command with newline in its name. It's also hard to imagine a scenario where someone could exploit a script that makes the assumption that $PATH won't contain newline characters.






share|improve this answer


























  • I'm saying that set -o noglob is more portable among the shells that can run that code if we want to consider zsh -o shwordsplit -o globsubst in that list. set -f is more portable among ancient Bourne-like shells, but those shells that don't support set -o noglob cannot run that code correctly anyway. When zsh was written in 1990, csh/tcsh were by far the most popular shells at the time. All of ksh/bash/zsh borrowed features from csh (...)

    – Stéphane Chazelas
    Jan 2 at 11:11











  • (...) csh had the -f option (for fast start) long before the Bourne shell added its -f to disable glob. So if you want to blame something for breaking compatibility, blame the Bourne (SysV) shell. There would be not reason why one would want to disable glob if it weren't for that bug of the Bourne shell whereby globbing is performed upon expansions. zsh fixed that bug, so set -o noglob is not needed there unless in sh emulation (where set -f works to disable it) or the globsubst option is enabled.

    – Stéphane Chazelas
    Jan 2 at 11:13





















1














Yes, PATH can contain newlines (even on ancient Unix system).



As to splitting any string in shell, the only way you can do it portably is with IFS. You can use IFS=:; set -f; set -- $PATH or pass it to a function instead of looping with for, though.



With bash you can also "read" a string into an array:



xtra=$'somenothernplacenn'; PATH="$PATH:$xtra"
mapfile -td: path < <(printf %s "$PATH")
printf '<%s>n' "${path[@]}"


But using arrays is usually not a good idea, because they can't be stored transparently in environment variables or passed as a single argument to external commands.



Notice that IFS will terminate fields, not separate them (kind of like n at the end of the file won't be treated like an empty line by programs reading the file line-by-line); if that's not what's expected, and you really want to create an extra empty field at the end when splitting a string that ends in a character from IFS, you should join an empty string after the variable that is subject to word splitting:



(P=/bin:; IFS=:; printf '<%s>n' $P"")
</bin>
<>


The word splitting algorithm will also ignore white space characters at the beginning of the string, if those whitespace characters are part of IFS. If you want an extra field for the leading whitespace, you should also join an empty string before the variable:



(P='   foo : bar  '; IFS=': '; set -f; set -- $P; printf '<%s>n' "$@")
<foo>
<bar>

(P=' foo : bar '; IFS=': '; set -f; set -- ""$P""; printf '<%s>n' "$@")
<>
<foo>
<bar>
<>





share|improve this answer


























  • Using arrays is often an excellent idea, as a number of answers here on unix.SE show. It's almost impossible to handle lists of strings with arbitrary data without using an array. You only need lists of paths with whitespace, or a list of command arguments to get the issue. Of course you can use the positional parameters instead of an array, but those aren't any better regarding the points you mention: they can't be sanely pushed through the environment, nor passed as a single argument to external commands.

    – ilkkachu
    Dec 31 '18 at 10:32











  • No, you need the set -f to take effect before the $PATH expansion. So it should be set -o noglob; set -- $PATH""

    – Stéphane Chazelas
    Dec 31 '18 at 10:41











  • @ilkkachu fwiw, quoting the here-string variable is not needed: x='a b'; mapfile -td: <<< $x y; printf '<%s>n' "$y"; but the added trailing newline is a problem, really.

    – pizdelect
    Dec 31 '18 at 12:14











  • @ilkkachu and that's documented in the bash manual, under "Here Strings": "Pathname expansion and word splitting are not performed"

    – pizdelect
    Dec 31 '18 at 12:25











  • @StéphaneChazelas thanks, I've changed it to use a process substitution instead.

    – pizdelect
    Dec 31 '18 at 12:36











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2 Answers
2






active

oldest

votes








2 Answers
2






active

oldest

votes









active

oldest

votes






active

oldest

votes









3














In POSIX shells, $IFS is a field delimiter, not separator, so a $PATH value like /bin:/usr/bin: would be split into /bin and /usr/bin instead of /bin, /usr/bin and the empty string (meaning the current directory). You need:



IFS=:; set -o noglob
for var in $PATH""; do
printf '<%s>n' "$var"
done


To avoid modifying global settings, you can use a shell with explicit splitting operators like zsh:



for var in "${(s/:/@)PATH}"; do
printf '<%s>n' "$var"
done


Though in that case, zsh already has the $path array tied to $PATH like in csh/tcsh, so:



for var in "$path[@]"; do
printf '<%s>n' "$var"
done


In any case, yes, in theory $PATH like any variable could contain newline characters, the newline character is not special in any way when it comes to file path resolution. I don't expect anyone sensible would put a directory with newline (or wildcards) in their $PATH or name a command with newline in its name. It's also hard to imagine a scenario where someone could exploit a script that makes the assumption that $PATH won't contain newline characters.






share|improve this answer


























  • I'm saying that set -o noglob is more portable among the shells that can run that code if we want to consider zsh -o shwordsplit -o globsubst in that list. set -f is more portable among ancient Bourne-like shells, but those shells that don't support set -o noglob cannot run that code correctly anyway. When zsh was written in 1990, csh/tcsh were by far the most popular shells at the time. All of ksh/bash/zsh borrowed features from csh (...)

    – Stéphane Chazelas
    Jan 2 at 11:11











  • (...) csh had the -f option (for fast start) long before the Bourne shell added its -f to disable glob. So if you want to blame something for breaking compatibility, blame the Bourne (SysV) shell. There would be not reason why one would want to disable glob if it weren't for that bug of the Bourne shell whereby globbing is performed upon expansions. zsh fixed that bug, so set -o noglob is not needed there unless in sh emulation (where set -f works to disable it) or the globsubst option is enabled.

    – Stéphane Chazelas
    Jan 2 at 11:13


















3














In POSIX shells, $IFS is a field delimiter, not separator, so a $PATH value like /bin:/usr/bin: would be split into /bin and /usr/bin instead of /bin, /usr/bin and the empty string (meaning the current directory). You need:



IFS=:; set -o noglob
for var in $PATH""; do
printf '<%s>n' "$var"
done


To avoid modifying global settings, you can use a shell with explicit splitting operators like zsh:



for var in "${(s/:/@)PATH}"; do
printf '<%s>n' "$var"
done


Though in that case, zsh already has the $path array tied to $PATH like in csh/tcsh, so:



for var in "$path[@]"; do
printf '<%s>n' "$var"
done


In any case, yes, in theory $PATH like any variable could contain newline characters, the newline character is not special in any way when it comes to file path resolution. I don't expect anyone sensible would put a directory with newline (or wildcards) in their $PATH or name a command with newline in its name. It's also hard to imagine a scenario where someone could exploit a script that makes the assumption that $PATH won't contain newline characters.






share|improve this answer


























  • I'm saying that set -o noglob is more portable among the shells that can run that code if we want to consider zsh -o shwordsplit -o globsubst in that list. set -f is more portable among ancient Bourne-like shells, but those shells that don't support set -o noglob cannot run that code correctly anyway. When zsh was written in 1990, csh/tcsh were by far the most popular shells at the time. All of ksh/bash/zsh borrowed features from csh (...)

    – Stéphane Chazelas
    Jan 2 at 11:11











  • (...) csh had the -f option (for fast start) long before the Bourne shell added its -f to disable glob. So if you want to blame something for breaking compatibility, blame the Bourne (SysV) shell. There would be not reason why one would want to disable glob if it weren't for that bug of the Bourne shell whereby globbing is performed upon expansions. zsh fixed that bug, so set -o noglob is not needed there unless in sh emulation (where set -f works to disable it) or the globsubst option is enabled.

    – Stéphane Chazelas
    Jan 2 at 11:13
















3












3








3







In POSIX shells, $IFS is a field delimiter, not separator, so a $PATH value like /bin:/usr/bin: would be split into /bin and /usr/bin instead of /bin, /usr/bin and the empty string (meaning the current directory). You need:



IFS=:; set -o noglob
for var in $PATH""; do
printf '<%s>n' "$var"
done


To avoid modifying global settings, you can use a shell with explicit splitting operators like zsh:



for var in "${(s/:/@)PATH}"; do
printf '<%s>n' "$var"
done


Though in that case, zsh already has the $path array tied to $PATH like in csh/tcsh, so:



for var in "$path[@]"; do
printf '<%s>n' "$var"
done


In any case, yes, in theory $PATH like any variable could contain newline characters, the newline character is not special in any way when it comes to file path resolution. I don't expect anyone sensible would put a directory with newline (or wildcards) in their $PATH or name a command with newline in its name. It's also hard to imagine a scenario where someone could exploit a script that makes the assumption that $PATH won't contain newline characters.






share|improve this answer















In POSIX shells, $IFS is a field delimiter, not separator, so a $PATH value like /bin:/usr/bin: would be split into /bin and /usr/bin instead of /bin, /usr/bin and the empty string (meaning the current directory). You need:



IFS=:; set -o noglob
for var in $PATH""; do
printf '<%s>n' "$var"
done


To avoid modifying global settings, you can use a shell with explicit splitting operators like zsh:



for var in "${(s/:/@)PATH}"; do
printf '<%s>n' "$var"
done


Though in that case, zsh already has the $path array tied to $PATH like in csh/tcsh, so:



for var in "$path[@]"; do
printf '<%s>n' "$var"
done


In any case, yes, in theory $PATH like any variable could contain newline characters, the newline character is not special in any way when it comes to file path resolution. I don't expect anyone sensible would put a directory with newline (or wildcards) in their $PATH or name a command with newline in its name. It's also hard to imagine a scenario where someone could exploit a script that makes the assumption that $PATH won't contain newline characters.







share|improve this answer














share|improve this answer



share|improve this answer








edited Dec 31 '18 at 11:17

























answered Dec 31 '18 at 10:46









Stéphane ChazelasStéphane Chazelas

308k57581939




308k57581939













  • I'm saying that set -o noglob is more portable among the shells that can run that code if we want to consider zsh -o shwordsplit -o globsubst in that list. set -f is more portable among ancient Bourne-like shells, but those shells that don't support set -o noglob cannot run that code correctly anyway. When zsh was written in 1990, csh/tcsh were by far the most popular shells at the time. All of ksh/bash/zsh borrowed features from csh (...)

    – Stéphane Chazelas
    Jan 2 at 11:11











  • (...) csh had the -f option (for fast start) long before the Bourne shell added its -f to disable glob. So if you want to blame something for breaking compatibility, blame the Bourne (SysV) shell. There would be not reason why one would want to disable glob if it weren't for that bug of the Bourne shell whereby globbing is performed upon expansions. zsh fixed that bug, so set -o noglob is not needed there unless in sh emulation (where set -f works to disable it) or the globsubst option is enabled.

    – Stéphane Chazelas
    Jan 2 at 11:13





















  • I'm saying that set -o noglob is more portable among the shells that can run that code if we want to consider zsh -o shwordsplit -o globsubst in that list. set -f is more portable among ancient Bourne-like shells, but those shells that don't support set -o noglob cannot run that code correctly anyway. When zsh was written in 1990, csh/tcsh were by far the most popular shells at the time. All of ksh/bash/zsh borrowed features from csh (...)

    – Stéphane Chazelas
    Jan 2 at 11:11











  • (...) csh had the -f option (for fast start) long before the Bourne shell added its -f to disable glob. So if you want to blame something for breaking compatibility, blame the Bourne (SysV) shell. There would be not reason why one would want to disable glob if it weren't for that bug of the Bourne shell whereby globbing is performed upon expansions. zsh fixed that bug, so set -o noglob is not needed there unless in sh emulation (where set -f works to disable it) or the globsubst option is enabled.

    – Stéphane Chazelas
    Jan 2 at 11:13



















I'm saying that set -o noglob is more portable among the shells that can run that code if we want to consider zsh -o shwordsplit -o globsubst in that list. set -f is more portable among ancient Bourne-like shells, but those shells that don't support set -o noglob cannot run that code correctly anyway. When zsh was written in 1990, csh/tcsh were by far the most popular shells at the time. All of ksh/bash/zsh borrowed features from csh (...)

– Stéphane Chazelas
Jan 2 at 11:11





I'm saying that set -o noglob is more portable among the shells that can run that code if we want to consider zsh -o shwordsplit -o globsubst in that list. set -f is more portable among ancient Bourne-like shells, but those shells that don't support set -o noglob cannot run that code correctly anyway. When zsh was written in 1990, csh/tcsh were by far the most popular shells at the time. All of ksh/bash/zsh borrowed features from csh (...)

– Stéphane Chazelas
Jan 2 at 11:11













(...) csh had the -f option (for fast start) long before the Bourne shell added its -f to disable glob. So if you want to blame something for breaking compatibility, blame the Bourne (SysV) shell. There would be not reason why one would want to disable glob if it weren't for that bug of the Bourne shell whereby globbing is performed upon expansions. zsh fixed that bug, so set -o noglob is not needed there unless in sh emulation (where set -f works to disable it) or the globsubst option is enabled.

– Stéphane Chazelas
Jan 2 at 11:13







(...) csh had the -f option (for fast start) long before the Bourne shell added its -f to disable glob. So if you want to blame something for breaking compatibility, blame the Bourne (SysV) shell. There would be not reason why one would want to disable glob if it weren't for that bug of the Bourne shell whereby globbing is performed upon expansions. zsh fixed that bug, so set -o noglob is not needed there unless in sh emulation (where set -f works to disable it) or the globsubst option is enabled.

– Stéphane Chazelas
Jan 2 at 11:13















1














Yes, PATH can contain newlines (even on ancient Unix system).



As to splitting any string in shell, the only way you can do it portably is with IFS. You can use IFS=:; set -f; set -- $PATH or pass it to a function instead of looping with for, though.



With bash you can also "read" a string into an array:



xtra=$'somenothernplacenn'; PATH="$PATH:$xtra"
mapfile -td: path < <(printf %s "$PATH")
printf '<%s>n' "${path[@]}"


But using arrays is usually not a good idea, because they can't be stored transparently in environment variables or passed as a single argument to external commands.



Notice that IFS will terminate fields, not separate them (kind of like n at the end of the file won't be treated like an empty line by programs reading the file line-by-line); if that's not what's expected, and you really want to create an extra empty field at the end when splitting a string that ends in a character from IFS, you should join an empty string after the variable that is subject to word splitting:



(P=/bin:; IFS=:; printf '<%s>n' $P"")
</bin>
<>


The word splitting algorithm will also ignore white space characters at the beginning of the string, if those whitespace characters are part of IFS. If you want an extra field for the leading whitespace, you should also join an empty string before the variable:



(P='   foo : bar  '; IFS=': '; set -f; set -- $P; printf '<%s>n' "$@")
<foo>
<bar>

(P=' foo : bar '; IFS=': '; set -f; set -- ""$P""; printf '<%s>n' "$@")
<>
<foo>
<bar>
<>





share|improve this answer


























  • Using arrays is often an excellent idea, as a number of answers here on unix.SE show. It's almost impossible to handle lists of strings with arbitrary data without using an array. You only need lists of paths with whitespace, or a list of command arguments to get the issue. Of course you can use the positional parameters instead of an array, but those aren't any better regarding the points you mention: they can't be sanely pushed through the environment, nor passed as a single argument to external commands.

    – ilkkachu
    Dec 31 '18 at 10:32











  • No, you need the set -f to take effect before the $PATH expansion. So it should be set -o noglob; set -- $PATH""

    – Stéphane Chazelas
    Dec 31 '18 at 10:41











  • @ilkkachu fwiw, quoting the here-string variable is not needed: x='a b'; mapfile -td: <<< $x y; printf '<%s>n' "$y"; but the added trailing newline is a problem, really.

    – pizdelect
    Dec 31 '18 at 12:14











  • @ilkkachu and that's documented in the bash manual, under "Here Strings": "Pathname expansion and word splitting are not performed"

    – pizdelect
    Dec 31 '18 at 12:25











  • @StéphaneChazelas thanks, I've changed it to use a process substitution instead.

    – pizdelect
    Dec 31 '18 at 12:36
















1














Yes, PATH can contain newlines (even on ancient Unix system).



As to splitting any string in shell, the only way you can do it portably is with IFS. You can use IFS=:; set -f; set -- $PATH or pass it to a function instead of looping with for, though.



With bash you can also "read" a string into an array:



xtra=$'somenothernplacenn'; PATH="$PATH:$xtra"
mapfile -td: path < <(printf %s "$PATH")
printf '<%s>n' "${path[@]}"


But using arrays is usually not a good idea, because they can't be stored transparently in environment variables or passed as a single argument to external commands.



Notice that IFS will terminate fields, not separate them (kind of like n at the end of the file won't be treated like an empty line by programs reading the file line-by-line); if that's not what's expected, and you really want to create an extra empty field at the end when splitting a string that ends in a character from IFS, you should join an empty string after the variable that is subject to word splitting:



(P=/bin:; IFS=:; printf '<%s>n' $P"")
</bin>
<>


The word splitting algorithm will also ignore white space characters at the beginning of the string, if those whitespace characters are part of IFS. If you want an extra field for the leading whitespace, you should also join an empty string before the variable:



(P='   foo : bar  '; IFS=': '; set -f; set -- $P; printf '<%s>n' "$@")
<foo>
<bar>

(P=' foo : bar '; IFS=': '; set -f; set -- ""$P""; printf '<%s>n' "$@")
<>
<foo>
<bar>
<>





share|improve this answer


























  • Using arrays is often an excellent idea, as a number of answers here on unix.SE show. It's almost impossible to handle lists of strings with arbitrary data without using an array. You only need lists of paths with whitespace, or a list of command arguments to get the issue. Of course you can use the positional parameters instead of an array, but those aren't any better regarding the points you mention: they can't be sanely pushed through the environment, nor passed as a single argument to external commands.

    – ilkkachu
    Dec 31 '18 at 10:32











  • No, you need the set -f to take effect before the $PATH expansion. So it should be set -o noglob; set -- $PATH""

    – Stéphane Chazelas
    Dec 31 '18 at 10:41











  • @ilkkachu fwiw, quoting the here-string variable is not needed: x='a b'; mapfile -td: <<< $x y; printf '<%s>n' "$y"; but the added trailing newline is a problem, really.

    – pizdelect
    Dec 31 '18 at 12:14











  • @ilkkachu and that's documented in the bash manual, under "Here Strings": "Pathname expansion and word splitting are not performed"

    – pizdelect
    Dec 31 '18 at 12:25











  • @StéphaneChazelas thanks, I've changed it to use a process substitution instead.

    – pizdelect
    Dec 31 '18 at 12:36














1












1








1







Yes, PATH can contain newlines (even on ancient Unix system).



As to splitting any string in shell, the only way you can do it portably is with IFS. You can use IFS=:; set -f; set -- $PATH or pass it to a function instead of looping with for, though.



With bash you can also "read" a string into an array:



xtra=$'somenothernplacenn'; PATH="$PATH:$xtra"
mapfile -td: path < <(printf %s "$PATH")
printf '<%s>n' "${path[@]}"


But using arrays is usually not a good idea, because they can't be stored transparently in environment variables or passed as a single argument to external commands.



Notice that IFS will terminate fields, not separate them (kind of like n at the end of the file won't be treated like an empty line by programs reading the file line-by-line); if that's not what's expected, and you really want to create an extra empty field at the end when splitting a string that ends in a character from IFS, you should join an empty string after the variable that is subject to word splitting:



(P=/bin:; IFS=:; printf '<%s>n' $P"")
</bin>
<>


The word splitting algorithm will also ignore white space characters at the beginning of the string, if those whitespace characters are part of IFS. If you want an extra field for the leading whitespace, you should also join an empty string before the variable:



(P='   foo : bar  '; IFS=': '; set -f; set -- $P; printf '<%s>n' "$@")
<foo>
<bar>

(P=' foo : bar '; IFS=': '; set -f; set -- ""$P""; printf '<%s>n' "$@")
<>
<foo>
<bar>
<>





share|improve this answer















Yes, PATH can contain newlines (even on ancient Unix system).



As to splitting any string in shell, the only way you can do it portably is with IFS. You can use IFS=:; set -f; set -- $PATH or pass it to a function instead of looping with for, though.



With bash you can also "read" a string into an array:



xtra=$'somenothernplacenn'; PATH="$PATH:$xtra"
mapfile -td: path < <(printf %s "$PATH")
printf '<%s>n' "${path[@]}"


But using arrays is usually not a good idea, because they can't be stored transparently in environment variables or passed as a single argument to external commands.



Notice that IFS will terminate fields, not separate them (kind of like n at the end of the file won't be treated like an empty line by programs reading the file line-by-line); if that's not what's expected, and you really want to create an extra empty field at the end when splitting a string that ends in a character from IFS, you should join an empty string after the variable that is subject to word splitting:



(P=/bin:; IFS=:; printf '<%s>n' $P"")
</bin>
<>


The word splitting algorithm will also ignore white space characters at the beginning of the string, if those whitespace characters are part of IFS. If you want an extra field for the leading whitespace, you should also join an empty string before the variable:



(P='   foo : bar  '; IFS=': '; set -f; set -- $P; printf '<%s>n' "$@")
<foo>
<bar>

(P=' foo : bar '; IFS=': '; set -f; set -- ""$P""; printf '<%s>n' "$@")
<>
<foo>
<bar>
<>






share|improve this answer














share|improve this answer



share|improve this answer








edited Jan 1 at 9:15

























answered Dec 31 '18 at 9:20









pizdelectpizdelect

67318




67318













  • Using arrays is often an excellent idea, as a number of answers here on unix.SE show. It's almost impossible to handle lists of strings with arbitrary data without using an array. You only need lists of paths with whitespace, or a list of command arguments to get the issue. Of course you can use the positional parameters instead of an array, but those aren't any better regarding the points you mention: they can't be sanely pushed through the environment, nor passed as a single argument to external commands.

    – ilkkachu
    Dec 31 '18 at 10:32











  • No, you need the set -f to take effect before the $PATH expansion. So it should be set -o noglob; set -- $PATH""

    – Stéphane Chazelas
    Dec 31 '18 at 10:41











  • @ilkkachu fwiw, quoting the here-string variable is not needed: x='a b'; mapfile -td: <<< $x y; printf '<%s>n' "$y"; but the added trailing newline is a problem, really.

    – pizdelect
    Dec 31 '18 at 12:14











  • @ilkkachu and that's documented in the bash manual, under "Here Strings": "Pathname expansion and word splitting are not performed"

    – pizdelect
    Dec 31 '18 at 12:25











  • @StéphaneChazelas thanks, I've changed it to use a process substitution instead.

    – pizdelect
    Dec 31 '18 at 12:36



















  • Using arrays is often an excellent idea, as a number of answers here on unix.SE show. It's almost impossible to handle lists of strings with arbitrary data without using an array. You only need lists of paths with whitespace, or a list of command arguments to get the issue. Of course you can use the positional parameters instead of an array, but those aren't any better regarding the points you mention: they can't be sanely pushed through the environment, nor passed as a single argument to external commands.

    – ilkkachu
    Dec 31 '18 at 10:32











  • No, you need the set -f to take effect before the $PATH expansion. So it should be set -o noglob; set -- $PATH""

    – Stéphane Chazelas
    Dec 31 '18 at 10:41











  • @ilkkachu fwiw, quoting the here-string variable is not needed: x='a b'; mapfile -td: <<< $x y; printf '<%s>n' "$y"; but the added trailing newline is a problem, really.

    – pizdelect
    Dec 31 '18 at 12:14











  • @ilkkachu and that's documented in the bash manual, under "Here Strings": "Pathname expansion and word splitting are not performed"

    – pizdelect
    Dec 31 '18 at 12:25











  • @StéphaneChazelas thanks, I've changed it to use a process substitution instead.

    – pizdelect
    Dec 31 '18 at 12:36

















Using arrays is often an excellent idea, as a number of answers here on unix.SE show. It's almost impossible to handle lists of strings with arbitrary data without using an array. You only need lists of paths with whitespace, or a list of command arguments to get the issue. Of course you can use the positional parameters instead of an array, but those aren't any better regarding the points you mention: they can't be sanely pushed through the environment, nor passed as a single argument to external commands.

– ilkkachu
Dec 31 '18 at 10:32





Using arrays is often an excellent idea, as a number of answers here on unix.SE show. It's almost impossible to handle lists of strings with arbitrary data without using an array. You only need lists of paths with whitespace, or a list of command arguments to get the issue. Of course you can use the positional parameters instead of an array, but those aren't any better regarding the points you mention: they can't be sanely pushed through the environment, nor passed as a single argument to external commands.

– ilkkachu
Dec 31 '18 at 10:32













No, you need the set -f to take effect before the $PATH expansion. So it should be set -o noglob; set -- $PATH""

– Stéphane Chazelas
Dec 31 '18 at 10:41





No, you need the set -f to take effect before the $PATH expansion. So it should be set -o noglob; set -- $PATH""

– Stéphane Chazelas
Dec 31 '18 at 10:41













@ilkkachu fwiw, quoting the here-string variable is not needed: x='a b'; mapfile -td: <<< $x y; printf '<%s>n' "$y"; but the added trailing newline is a problem, really.

– pizdelect
Dec 31 '18 at 12:14





@ilkkachu fwiw, quoting the here-string variable is not needed: x='a b'; mapfile -td: <<< $x y; printf '<%s>n' "$y"; but the added trailing newline is a problem, really.

– pizdelect
Dec 31 '18 at 12:14













@ilkkachu and that's documented in the bash manual, under "Here Strings": "Pathname expansion and word splitting are not performed"

– pizdelect
Dec 31 '18 at 12:25





@ilkkachu and that's documented in the bash manual, under "Here Strings": "Pathname expansion and word splitting are not performed"

– pizdelect
Dec 31 '18 at 12:25













@StéphaneChazelas thanks, I've changed it to use a process substitution instead.

– pizdelect
Dec 31 '18 at 12:36





@StéphaneChazelas thanks, I've changed it to use a process substitution instead.

– pizdelect
Dec 31 '18 at 12:36


















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