In which condition an integral corresponds to the measure of the integration domain? [on hold]











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[edited]When calculating the integral(Iterated integral) of the function f (x, y) = 1, we will find the measure of the integration domain.
Example: if f (x, y) = 1, then the double integrals gives the area of ​​region R
An explanation for this is that the integration interval coincides with the contour of the region and in this case the region (area) being integrated by this function



My doubt is how I describe, perhaps, by creating a theorem, that given certain conditions, the result of the integral will coincide with the measure of the integration domain










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put on hold as unclear what you're asking by Kavi Rama Murthy, GNUSupporter 8964民主女神 地下教會, Rebellos, Paul Frost, ancientmathematician 15 hours ago


Please clarify your specific problem or add additional details to highlight exactly what you need. As it's currently written, it’s hard to tell exactly what you're asking. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.











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    Welcome to MSE. Your question is phrased as an isolated problem, without any further information or context. This does not match many users' quality standards, so it may attract downvotes, or be put on hold. To prevent that, please edit the question. This will help you recognise and resolve the issues. Concretely: please provide context, and include your work and thoughts on the problem. These changes can help in formulating more appropriate answers.
    – José Carlos Santos
    17 hours ago










  • Thanks for the warning, the question has now been edited, I hope it's understandable
    – Gean Machado
    13 hours ago















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[edited]When calculating the integral(Iterated integral) of the function f (x, y) = 1, we will find the measure of the integration domain.
Example: if f (x, y) = 1, then the double integrals gives the area of ​​region R
An explanation for this is that the integration interval coincides with the contour of the region and in this case the region (area) being integrated by this function



My doubt is how I describe, perhaps, by creating a theorem, that given certain conditions, the result of the integral will coincide with the measure of the integration domain










share|cite|improve this question









New contributor




Gean Machado is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











put on hold as unclear what you're asking by Kavi Rama Murthy, GNUSupporter 8964民主女神 地下教會, Rebellos, Paul Frost, ancientmathematician 15 hours ago


Please clarify your specific problem or add additional details to highlight exactly what you need. As it's currently written, it’s hard to tell exactly what you're asking. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.











  • 1




    Welcome to MSE. Your question is phrased as an isolated problem, without any further information or context. This does not match many users' quality standards, so it may attract downvotes, or be put on hold. To prevent that, please edit the question. This will help you recognise and resolve the issues. Concretely: please provide context, and include your work and thoughts on the problem. These changes can help in formulating more appropriate answers.
    – José Carlos Santos
    17 hours ago










  • Thanks for the warning, the question has now been edited, I hope it's understandable
    – Gean Machado
    13 hours ago













up vote
0
down vote

favorite









up vote
0
down vote

favorite











[edited]When calculating the integral(Iterated integral) of the function f (x, y) = 1, we will find the measure of the integration domain.
Example: if f (x, y) = 1, then the double integrals gives the area of ​​region R
An explanation for this is that the integration interval coincides with the contour of the region and in this case the region (area) being integrated by this function



My doubt is how I describe, perhaps, by creating a theorem, that given certain conditions, the result of the integral will coincide with the measure of the integration domain










share|cite|improve this question









New contributor




Gean Machado is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











[edited]When calculating the integral(Iterated integral) of the function f (x, y) = 1, we will find the measure of the integration domain.
Example: if f (x, y) = 1, then the double integrals gives the area of ​​region R
An explanation for this is that the integration interval coincides with the contour of the region and in this case the region (area) being integrated by this function



My doubt is how I describe, perhaps, by creating a theorem, that given certain conditions, the result of the integral will coincide with the measure of the integration domain







integration






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Gean Machado is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











share|cite|improve this question









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Gean Machado is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









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edited 13 hours ago





















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asked 18 hours ago









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New contributor





Gean Machado is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






Gean Machado is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.




put on hold as unclear what you're asking by Kavi Rama Murthy, GNUSupporter 8964民主女神 地下教會, Rebellos, Paul Frost, ancientmathematician 15 hours ago


Please clarify your specific problem or add additional details to highlight exactly what you need. As it's currently written, it’s hard to tell exactly what you're asking. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.






put on hold as unclear what you're asking by Kavi Rama Murthy, GNUSupporter 8964民主女神 地下教會, Rebellos, Paul Frost, ancientmathematician 15 hours ago


Please clarify your specific problem or add additional details to highlight exactly what you need. As it's currently written, it’s hard to tell exactly what you're asking. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.










  • 1




    Welcome to MSE. Your question is phrased as an isolated problem, without any further information or context. This does not match many users' quality standards, so it may attract downvotes, or be put on hold. To prevent that, please edit the question. This will help you recognise and resolve the issues. Concretely: please provide context, and include your work and thoughts on the problem. These changes can help in formulating more appropriate answers.
    – José Carlos Santos
    17 hours ago










  • Thanks for the warning, the question has now been edited, I hope it's understandable
    – Gean Machado
    13 hours ago














  • 1




    Welcome to MSE. Your question is phrased as an isolated problem, without any further information or context. This does not match many users' quality standards, so it may attract downvotes, or be put on hold. To prevent that, please edit the question. This will help you recognise and resolve the issues. Concretely: please provide context, and include your work and thoughts on the problem. These changes can help in formulating more appropriate answers.
    – José Carlos Santos
    17 hours ago










  • Thanks for the warning, the question has now been edited, I hope it's understandable
    – Gean Machado
    13 hours ago








1




1




Welcome to MSE. Your question is phrased as an isolated problem, without any further information or context. This does not match many users' quality standards, so it may attract downvotes, or be put on hold. To prevent that, please edit the question. This will help you recognise and resolve the issues. Concretely: please provide context, and include your work and thoughts on the problem. These changes can help in formulating more appropriate answers.
– José Carlos Santos
17 hours ago




Welcome to MSE. Your question is phrased as an isolated problem, without any further information or context. This does not match many users' quality standards, so it may attract downvotes, or be put on hold. To prevent that, please edit the question. This will help you recognise and resolve the issues. Concretely: please provide context, and include your work and thoughts on the problem. These changes can help in formulating more appropriate answers.
– José Carlos Santos
17 hours ago












Thanks for the warning, the question has now been edited, I hope it's understandable
– Gean Machado
13 hours ago




Thanks for the warning, the question has now been edited, I hope it's understandable
– Gean Machado
13 hours ago















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