Estimating powers of $e$ [closed]
1
$begingroup$
In a PChem homework,the final step is to calculate $e^{-3/2}$. Since it is a HW problem, I just punched a calculator to get the answer.
But unfortunately calculators are not allowed for exams. So what if I find myself in this situation in the midterm? How can I quickly estimate such a power?
exponential-function
edited Jan 16 at 4:31
Andrews
1,3112423
asked Jan 15 at 21:17
ZeyuanZeyuan
1273
$endgroup$
closed as off-topic by Somos, Lord Shark the Unknown, Chris Custer, Cesareo, ancientmathematician Jan 16 at 7:47
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Somos, Lord Shark the Unknown, Chris Custer, Cesareo, ancientmathematician
If this question can be reworded to fit the rules in the help center, please edit the question.
|
show 3 more comments
1
$begingroup$
In a PChem homework,the final step is to calculate $e^{-3/2}$. Since it is a HW problem, I just punched a calculator to get the answer.
But unfortunately calculators are not allowed for exams. So what if I find myself in this situation in the midterm? How can I quickly estimate such a power?
exponential-function
edited Jan 16 at 4:31
Andrews
1,3112423
asked Jan 15 at 21:17
ZeyuanZeyuan
1273
$endgroup$
closed as off-topic by Somos, Lord Shark the Unknown, Chris Custer, Cesareo, ancientmathematician Jan 16 at 7:47
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Somos, Lord Shark the Unknown, Chris Custer, Cesareo, ancientmathematician
If this question can be reworded to fit the rules in the help center, please edit the question.
3
$begingroup$
Taylor series with a small number of terms?
$endgroup$
– MPW
Jan 15 at 21:18
$begingroup$
Are you allowed to know the value of $e$?
$endgroup$
– user
Jan 15 at 21:29
$begingroup$
Do they give you log tables?
$endgroup$
– Aditya Dua
Jan 15 at 21:36
$begingroup$
$e^3 = 20$ is a decent approximation. So you can write the final answer as ${1 over sqrt{20}} = {1 over 2 sqrt{5}}$.
$endgroup$
– Aditya Dua
Jan 15 at 21:39
2
$begingroup$
This question is better answered by your instructor. Only he/she knows what you are allowed/required to do. By the way, 1 is an estimate for any positive real number. In your case 1/5 is even better, but all numbers are estimates in the end.
$endgroup$
– Somos
Jan 15 at 23:46
|
show 3 more comments
1
1
1
$begingroup$
In a PChem homework,the final step is to calculate $e^{-3/2}$. Since it is a HW problem, I just punched a calculator to get the answer.
But unfortunately calculators are not allowed for exams. So what if I find myself in this situation in the midterm? How can I quickly estimate such a power?
exponential-function
edited Jan 16 at 4:31
Andrews
1,3112423
asked Jan 15 at 21:17
ZeyuanZeyuan
1273
$endgroup$
In a PChem homework,the final step is to calculate $e^{-3/2}$. Since it is a HW problem, I just punched a calculator to get the answer.
But unfortunately calculators are not allowed for exams. So what if I find myself in this situation in the midterm? How can I quickly estimate such a power?
exponential-function
exponential-function
edited Jan 16 at 4:31
Andrews
1,3112423
asked Jan 15 at 21:17
ZeyuanZeyuan
1273
edited Jan 16 at 4:31
Andrews
1,3112423
asked Jan 15 at 21:17
ZeyuanZeyuan
1273
edited Jan 16 at 4:31
Andrews
1,3112423
edited Jan 16 at 4:31
Andrews
1,3112423
edited Jan 16 at 4:31
Andrews
1,3112423
1,3112423
asked Jan 15 at 21:17
ZeyuanZeyuan
1273
asked Jan 15 at 21:17
ZeyuanZeyuan
1273
asked Jan 15 at 21:17
ZeyuanZeyuan
1273
1273
closed as off-topic by Somos, Lord Shark the Unknown, Chris Custer, Cesareo, ancientmathematician Jan 16 at 7:47
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Somos, Lord Shark the Unknown, Chris Custer, Cesareo, ancientmathematician
If this question can be reworded to fit the rules in the help center, please edit the question.
closed as off-topic by Somos, Lord Shark the Unknown, Chris Custer, Cesareo, ancientmathematician Jan 16 at 7:47
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Somos, Lord Shark the Unknown, Chris Custer, Cesareo, ancientmathematician
If this question can be reworded to fit the rules in the help center, please edit the question.
3
$begingroup$
Taylor series with a small number of terms?
$endgroup$
– MPW
Jan 15 at 21:18
$begingroup$
Are you allowed to know the value of $e$?
$endgroup$
– user
Jan 15 at 21:29
$begingroup$
Do they give you log tables?
$endgroup$
– Aditya Dua
Jan 15 at 21:36
$begingroup$
$e^3 = 20$ is a decent approximation. So you can write the final answer as ${1 over sqrt{20}} = {1 over 2 sqrt{5}}$.
$endgroup$
– Aditya Dua
Jan 15 at 21:39
2
$begingroup$
This question is better answered by your instructor. Only he/she knows what you are allowed/required to do. By the way, 1 is an estimate for any positive real number. In your case 1/5 is even better, but all numbers are estimates in the end.
$endgroup$
– Somos
Jan 15 at 23:46
|
show 3 more comments
3
$begingroup$
Taylor series with a small number of terms?
$endgroup$
– MPW
Jan 15 at 21:18
$begingroup$
Are you allowed to know the value of $e$?
$endgroup$
– user
Jan 15 at 21:29
$begingroup$
Do they give you log tables?
$endgroup$
– Aditya Dua
Jan 15 at 21:36
$begingroup$
$e^3 = 20$ is a decent approximation. So you can write the final answer as ${1 over sqrt{20}} = {1 over 2 sqrt{5}}$.
$endgroup$
– Aditya Dua
Jan 15 at 21:39
2
$begingroup$
This question is better answered by your instructor. Only he/she knows what you are allowed/required to do. By the way, 1 is an estimate for any positive real number. In your case 1/5 is even better, but all numbers are estimates in the end.
$endgroup$
– Somos
Jan 15 at 23:46
3
3
$begingroup$
Taylor series with a small number of terms?
$endgroup$
– MPW
Jan 15 at 21:18
$begingroup$
Taylor series with a small number of terms?
$endgroup$
– MPW
Jan 15 at 21:18
$begingroup$
Are you allowed to know the value of $e$?
$endgroup$
– user
Jan 15 at 21:29
$begingroup$
Are you allowed to know the value of $e$?
$endgroup$
– user
Jan 15 at 21:29
$begingroup$
Do they give you log tables?
$endgroup$
– Aditya Dua
Jan 15 at 21:36
$begingroup$
Do they give you log tables?
$endgroup$
– Aditya Dua
Jan 15 at 21:36
$begingroup$
$e^3 = 20$ is a decent approximation. So you can write the final answer as ${1 over sqrt{20}} = {1 over 2 sqrt{5}}$.
$endgroup$
– Aditya Dua
Jan 15 at 21:39
$begingroup$
$e^3 = 20$ is a decent approximation. So you can write the final answer as ${1 over sqrt{20}} = {1 over 2 sqrt{5}}$.
$endgroup$
– Aditya Dua
Jan 15 at 21:39
2
2
$begingroup$
This question is better answered by your instructor. Only he/she knows what you are allowed/required to do. By the way, 1 is an estimate for any positive real number. In your case 1/5 is even better, but all numbers are estimates in the end.
$endgroup$
– Somos
Jan 15 at 23:46
$begingroup$
This question is better answered by your instructor. Only he/she knows what you are allowed/required to do. By the way, 1 is an estimate for any positive real number. In your case 1/5 is even better, but all numbers are estimates in the end.
$endgroup$
– Somos
Jan 15 at 23:46
|
show 3 more comments
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3
$begingroup$
Taylor series with a small number of terms?
$endgroup$
– MPW
Jan 15 at 21:18
$begingroup$
Are you allowed to know the value of $e$?
$endgroup$
– user
Jan 15 at 21:29
$begingroup$
Do they give you log tables?
$endgroup$
– Aditya Dua
Jan 15 at 21:36
$begingroup$
$e^3 = 20$ is a decent approximation. So you can write the final answer as ${1 over sqrt{20}} = {1 over 2 sqrt{5}}$.
$endgroup$
– Aditya Dua
Jan 15 at 21:39
2
$begingroup$
This question is better answered by your instructor. Only he/she knows what you are allowed/required to do. By the way, 1 is an estimate for any positive real number. In your case 1/5 is even better, but all numbers are estimates in the end.
$endgroup$
– Somos
Jan 15 at 23:46