What does it mean that “general states are not conserving probability so, it could be neither a quantum...












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Since $hat{H}$ is Hermitian matrix, its eigenvalues are real numbers. Components with positive eigenvalues decrease to zero and negative eigenvalues blow up to infinity. The only stable solutions are the one that corresponding to 0 eigenvalue. It implies that general states are not conserving probability. So, it could be neither a quantum system, nor a Markov chain.





  1. What does that mean that "general states are not conserving probability so, it could be neither a quantum system, nor a Markov chain" ?


  2. So we're not even talking about processes?


  3. Why in a quantum system general states are probability conservated ?










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    0












    $begingroup$


    I read from here




    Since $hat{H}$ is Hermitian matrix, its eigenvalues are real numbers. Components with positive eigenvalues decrease to zero and negative eigenvalues blow up to infinity. The only stable solutions are the one that corresponding to 0 eigenvalue. It implies that general states are not conserving probability. So, it could be neither a quantum system, nor a Markov chain.





    1. What does that mean that "general states are not conserving probability so, it could be neither a quantum system, nor a Markov chain" ?


    2. So we're not even talking about processes?


    3. Why in a quantum system general states are probability conservated ?










    share|cite|improve this question









    $endgroup$















      0












      0








      0





      $begingroup$


      I read from here




      Since $hat{H}$ is Hermitian matrix, its eigenvalues are real numbers. Components with positive eigenvalues decrease to zero and negative eigenvalues blow up to infinity. The only stable solutions are the one that corresponding to 0 eigenvalue. It implies that general states are not conserving probability. So, it could be neither a quantum system, nor a Markov chain.





      1. What does that mean that "general states are not conserving probability so, it could be neither a quantum system, nor a Markov chain" ?


      2. So we're not even talking about processes?


      3. Why in a quantum system general states are probability conservated ?










      share|cite|improve this question









      $endgroup$




      I read from here




      Since $hat{H}$ is Hermitian matrix, its eigenvalues are real numbers. Components with positive eigenvalues decrease to zero and negative eigenvalues blow up to infinity. The only stable solutions are the one that corresponding to 0 eigenvalue. It implies that general states are not conserving probability. So, it could be neither a quantum system, nor a Markov chain.





      1. What does that mean that "general states are not conserving probability so, it could be neither a quantum system, nor a Markov chain" ?


      2. So we're not even talking about processes?


      3. Why in a quantum system general states are probability conservated ?







      markov-process hidden-markov-models






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      share|cite|improve this question











      share|cite|improve this question




      share|cite|improve this question










      asked Jan 14 at 0:10









      KenKen

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