What does it mean that “general states are not conserving probability so, it could be neither a quantum...
$begingroup$
I read from here
Since $hat{H}$ is Hermitian matrix, its eigenvalues are real numbers. Components with positive eigenvalues decrease to zero and negative eigenvalues blow up to infinity. The only stable solutions are the one that corresponding to 0 eigenvalue. It implies that general states are not conserving probability. So, it could be neither a quantum system, nor a Markov chain.
What does that mean that "general states are not conserving probability so, it could be neither a quantum system, nor a Markov chain" ?
So we're not even talking about processes?
- Why in a quantum system general states are probability conservated ?
markov-process hidden-markov-models
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add a comment |
$begingroup$
I read from here
Since $hat{H}$ is Hermitian matrix, its eigenvalues are real numbers. Components with positive eigenvalues decrease to zero and negative eigenvalues blow up to infinity. The only stable solutions are the one that corresponding to 0 eigenvalue. It implies that general states are not conserving probability. So, it could be neither a quantum system, nor a Markov chain.
What does that mean that "general states are not conserving probability so, it could be neither a quantum system, nor a Markov chain" ?
So we're not even talking about processes?
- Why in a quantum system general states are probability conservated ?
markov-process hidden-markov-models
$endgroup$
add a comment |
$begingroup$
I read from here
Since $hat{H}$ is Hermitian matrix, its eigenvalues are real numbers. Components with positive eigenvalues decrease to zero and negative eigenvalues blow up to infinity. The only stable solutions are the one that corresponding to 0 eigenvalue. It implies that general states are not conserving probability. So, it could be neither a quantum system, nor a Markov chain.
What does that mean that "general states are not conserving probability so, it could be neither a quantum system, nor a Markov chain" ?
So we're not even talking about processes?
- Why in a quantum system general states are probability conservated ?
markov-process hidden-markov-models
$endgroup$
I read from here
Since $hat{H}$ is Hermitian matrix, its eigenvalues are real numbers. Components with positive eigenvalues decrease to zero and negative eigenvalues blow up to infinity. The only stable solutions are the one that corresponding to 0 eigenvalue. It implies that general states are not conserving probability. So, it could be neither a quantum system, nor a Markov chain.
What does that mean that "general states are not conserving probability so, it could be neither a quantum system, nor a Markov chain" ?
So we're not even talking about processes?
- Why in a quantum system general states are probability conservated ?
markov-process hidden-markov-models
markov-process hidden-markov-models
asked Jan 14 at 0:10
KenKen
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