If $fin C_0(mathbb R)cap C^2(mathbb R)$, is $bf'+frac12sigma^2f''in C_0(mathbb R)$?












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$begingroup$


Let





  • $b,sigma:mathbb R$ be Lipschitz continuous with $$|b(x)|^2+|sigma(x)|^2le C(1+|x|^2);;;text{for all }xinmathbb Rtag1,$$ $sigmain C^2(mathbb R)$, $sigma''$ being bounded and $sigma(mathbb R)subseteqmathbb Rsetminusleft{0right}$


  • $C_0(mathbb R)$ denote the space of continuous functions vanishing at infinity


If $fin C_0(mathbb R)cap C^2(mathbb R)$, are we able to show that $$Lf:=bf'+frac12sigma^2f''in C_0(mathbb R)$$ or is there an example of such an $f$ with $Lfnotin C_0(mathbb R)$?










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$endgroup$

















    0












    $begingroup$


    Let





    • $b,sigma:mathbb R$ be Lipschitz continuous with $$|b(x)|^2+|sigma(x)|^2le C(1+|x|^2);;;text{for all }xinmathbb Rtag1,$$ $sigmain C^2(mathbb R)$, $sigma''$ being bounded and $sigma(mathbb R)subseteqmathbb Rsetminusleft{0right}$


    • $C_0(mathbb R)$ denote the space of continuous functions vanishing at infinity


    If $fin C_0(mathbb R)cap C^2(mathbb R)$, are we able to show that $$Lf:=bf'+frac12sigma^2f''in C_0(mathbb R)$$ or is there an example of such an $f$ with $Lfnotin C_0(mathbb R)$?










    share|cite|improve this question











    $endgroup$















      0












      0








      0





      $begingroup$


      Let





      • $b,sigma:mathbb R$ be Lipschitz continuous with $$|b(x)|^2+|sigma(x)|^2le C(1+|x|^2);;;text{for all }xinmathbb Rtag1,$$ $sigmain C^2(mathbb R)$, $sigma''$ being bounded and $sigma(mathbb R)subseteqmathbb Rsetminusleft{0right}$


      • $C_0(mathbb R)$ denote the space of continuous functions vanishing at infinity


      If $fin C_0(mathbb R)cap C^2(mathbb R)$, are we able to show that $$Lf:=bf'+frac12sigma^2f''in C_0(mathbb R)$$ or is there an example of such an $f$ with $Lfnotin C_0(mathbb R)$?










      share|cite|improve this question











      $endgroup$




      Let





      • $b,sigma:mathbb R$ be Lipschitz continuous with $$|b(x)|^2+|sigma(x)|^2le C(1+|x|^2);;;text{for all }xinmathbb Rtag1,$$ $sigmain C^2(mathbb R)$, $sigma''$ being bounded and $sigma(mathbb R)subseteqmathbb Rsetminusleft{0right}$


      • $C_0(mathbb R)$ denote the space of continuous functions vanishing at infinity


      If $fin C_0(mathbb R)cap C^2(mathbb R)$, are we able to show that $$Lf:=bf'+frac12sigma^2f''in C_0(mathbb R)$$ or is there an example of such an $f$ with $Lfnotin C_0(mathbb R)$?







      functional-analysis derivatives distribution-theory






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      share|cite|improve this question








      edited Dec 27 '18 at 0:36









      mathworker21

      8,9421928




      8,9421928










      asked Dec 26 '18 at 22:57









      0xbadf00d0xbadf00d

      1,95841531




      1,95841531






















          1 Answer
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          $begingroup$

          There are definitely examples of such $f$ with $Lf not in C_0(mathbb{R})$. Take some $f$ that does go to infinity but whose derivative is greater than $1$ in magnitude nearly always (one can visualize such a thing as a smoothed out version of a bunch of spikes with lengths tending to $0$). Then if we take $b equiv 1$ and $sigma$ some function that quickly goes to $0$ at infinity, we see $Lf approx f'$ does not go to $0$.






          share|cite|improve this answer









          $endgroup$













          • $begingroup$
            Could you provide a concrete example for such a $f$?
            $endgroup$
            – 0xbadf00d
            Dec 29 '18 at 16:22










          • $begingroup$
            @0xbadf00d cmon. if you read/understand my solution, I won't need to
            $endgroup$
            – mathworker21
            Dec 29 '18 at 23:10











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          0












          $begingroup$

          There are definitely examples of such $f$ with $Lf not in C_0(mathbb{R})$. Take some $f$ that does go to infinity but whose derivative is greater than $1$ in magnitude nearly always (one can visualize such a thing as a smoothed out version of a bunch of spikes with lengths tending to $0$). Then if we take $b equiv 1$ and $sigma$ some function that quickly goes to $0$ at infinity, we see $Lf approx f'$ does not go to $0$.






          share|cite|improve this answer









          $endgroup$













          • $begingroup$
            Could you provide a concrete example for such a $f$?
            $endgroup$
            – 0xbadf00d
            Dec 29 '18 at 16:22










          • $begingroup$
            @0xbadf00d cmon. if you read/understand my solution, I won't need to
            $endgroup$
            – mathworker21
            Dec 29 '18 at 23:10
















          0












          $begingroup$

          There are definitely examples of such $f$ with $Lf not in C_0(mathbb{R})$. Take some $f$ that does go to infinity but whose derivative is greater than $1$ in magnitude nearly always (one can visualize such a thing as a smoothed out version of a bunch of spikes with lengths tending to $0$). Then if we take $b equiv 1$ and $sigma$ some function that quickly goes to $0$ at infinity, we see $Lf approx f'$ does not go to $0$.






          share|cite|improve this answer









          $endgroup$













          • $begingroup$
            Could you provide a concrete example for such a $f$?
            $endgroup$
            – 0xbadf00d
            Dec 29 '18 at 16:22










          • $begingroup$
            @0xbadf00d cmon. if you read/understand my solution, I won't need to
            $endgroup$
            – mathworker21
            Dec 29 '18 at 23:10














          0












          0








          0





          $begingroup$

          There are definitely examples of such $f$ with $Lf not in C_0(mathbb{R})$. Take some $f$ that does go to infinity but whose derivative is greater than $1$ in magnitude nearly always (one can visualize such a thing as a smoothed out version of a bunch of spikes with lengths tending to $0$). Then if we take $b equiv 1$ and $sigma$ some function that quickly goes to $0$ at infinity, we see $Lf approx f'$ does not go to $0$.






          share|cite|improve this answer









          $endgroup$



          There are definitely examples of such $f$ with $Lf not in C_0(mathbb{R})$. Take some $f$ that does go to infinity but whose derivative is greater than $1$ in magnitude nearly always (one can visualize such a thing as a smoothed out version of a bunch of spikes with lengths tending to $0$). Then if we take $b equiv 1$ and $sigma$ some function that quickly goes to $0$ at infinity, we see $Lf approx f'$ does not go to $0$.







          share|cite|improve this answer












          share|cite|improve this answer



          share|cite|improve this answer










          answered Dec 27 '18 at 0:45









          mathworker21mathworker21

          8,9421928




          8,9421928












          • $begingroup$
            Could you provide a concrete example for such a $f$?
            $endgroup$
            – 0xbadf00d
            Dec 29 '18 at 16:22










          • $begingroup$
            @0xbadf00d cmon. if you read/understand my solution, I won't need to
            $endgroup$
            – mathworker21
            Dec 29 '18 at 23:10


















          • $begingroup$
            Could you provide a concrete example for such a $f$?
            $endgroup$
            – 0xbadf00d
            Dec 29 '18 at 16:22










          • $begingroup$
            @0xbadf00d cmon. if you read/understand my solution, I won't need to
            $endgroup$
            – mathworker21
            Dec 29 '18 at 23:10
















          $begingroup$
          Could you provide a concrete example for such a $f$?
          $endgroup$
          – 0xbadf00d
          Dec 29 '18 at 16:22




          $begingroup$
          Could you provide a concrete example for such a $f$?
          $endgroup$
          – 0xbadf00d
          Dec 29 '18 at 16:22












          $begingroup$
          @0xbadf00d cmon. if you read/understand my solution, I won't need to
          $endgroup$
          – mathworker21
          Dec 29 '18 at 23:10




          $begingroup$
          @0xbadf00d cmon. if you read/understand my solution, I won't need to
          $endgroup$
          – mathworker21
          Dec 29 '18 at 23:10


















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