Null and Alternative Hypothesis
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My task for the 2 following problems is to identify the null value and alternative value. I know similar questions have been asked, and I've looked at them and I think I understand it. But I keep getting this question wrong
Question 1: Perform hypothesis test for population proportion
It is known that 29% of the months have rice production by Company1 above 307200 cwt (company1>307200.0). Is there sufficient evidence to suggest that the proportion is less than 29%? Test at 5% level of significance.
My answer:
Null = .29
alternative = .01
Question 2: Perform hypothesis test for population mean
It is claimed that average rice production by Company2 is 209,500 cwt (Company2 = 209500.0). Test this claim using a hypothesis test at 1% level of significance.
My answer:
Null = 209500.0
alternative = .01
I'm being told that these my answers are not correct. I have no idea why. Any help would be appreciated!
statistics
asked Jan 14 at 22:09
BrianBrian
1
$endgroup$
add a comment |
$begingroup$
My task for the 2 following problems is to identify the null value and alternative value. I know similar questions have been asked, and I've looked at them and I think I understand it. But I keep getting this question wrong
Question 1: Perform hypothesis test for population proportion
It is known that 29% of the months have rice production by Company1 above 307200 cwt (company1>307200.0). Is there sufficient evidence to suggest that the proportion is less than 29%? Test at 5% level of significance.
My answer:
Null = .29
alternative = .01
Question 2: Perform hypothesis test for population mean
It is claimed that average rice production by Company2 is 209,500 cwt (Company2 = 209500.0). Test this claim using a hypothesis test at 1% level of significance.
My answer:
Null = 209500.0
alternative = .01
I'm being told that these my answers are not correct. I have no idea why. Any help would be appreciated!
statistics
asked Jan 14 at 22:09
BrianBrian
1
$endgroup$
$begingroup$
Your formatting for this is incorrect, Null is not equal to 0.29, The correct way to state this is Null: p = 0.29, Also why are you saying alternative = 0.1? I can understand what you meant by the incorrect notation, but they are asking if the proportion is less than 29%, where did the 0.01 come from? Alternative should be p < 0.29 (Someone please correct me if I am wrong, It has been a while since I've done applied statistics)
$endgroup$
– Wallace
Jan 14 at 22:39
$begingroup$
Sorry! I messed that up, In question one I believe the alternative = .05. I was under the impression that if you have a specific test case (such as the .05) that that was the alternative value
$endgroup$
– Brian
Jan 14 at 22:46
$begingroup$
$0.05$ and $0.01$ are the levels of significance of the tests but not the alternative hypotheses.
$endgroup$
– Henry
Jan 15 at 10:47
add a comment |
$begingroup$
My task for the 2 following problems is to identify the null value and alternative value. I know similar questions have been asked, and I've looked at them and I think I understand it. But I keep getting this question wrong
Question 1: Perform hypothesis test for population proportion
It is known that 29% of the months have rice production by Company1 above 307200 cwt (company1>307200.0). Is there sufficient evidence to suggest that the proportion is less than 29%? Test at 5% level of significance.
My answer:
Null = .29
alternative = .01
Question 2: Perform hypothesis test for population mean
It is claimed that average rice production by Company2 is 209,500 cwt (Company2 = 209500.0). Test this claim using a hypothesis test at 1% level of significance.
My answer:
Null = 209500.0
alternative = .01
I'm being told that these my answers are not correct. I have no idea why. Any help would be appreciated!
statistics
asked Jan 14 at 22:09
BrianBrian
1
$endgroup$
My task for the 2 following problems is to identify the null value and alternative value. I know similar questions have been asked, and I've looked at them and I think I understand it. But I keep getting this question wrong
Question 1: Perform hypothesis test for population proportion
It is known that 29% of the months have rice production by Company1 above 307200 cwt (company1>307200.0). Is there sufficient evidence to suggest that the proportion is less than 29%? Test at 5% level of significance.
My answer:
Null = .29
alternative = .01
Question 2: Perform hypothesis test for population mean
It is claimed that average rice production by Company2 is 209,500 cwt (Company2 = 209500.0). Test this claim using a hypothesis test at 1% level of significance.
My answer:
Null = 209500.0
alternative = .01
I'm being told that these my answers are not correct. I have no idea why. Any help would be appreciated!
statistics
statistics
asked Jan 14 at 22:09
BrianBrian
1
asked Jan 14 at 22:09
BrianBrian
1
asked Jan 14 at 22:09
BrianBrian
1
asked Jan 14 at 22:09
BrianBrian
1
asked Jan 14 at 22:09
BrianBrian
1
1
$begingroup$
Your formatting for this is incorrect, Null is not equal to 0.29, The correct way to state this is Null: p = 0.29, Also why are you saying alternative = 0.1? I can understand what you meant by the incorrect notation, but they are asking if the proportion is less than 29%, where did the 0.01 come from? Alternative should be p < 0.29 (Someone please correct me if I am wrong, It has been a while since I've done applied statistics)
$endgroup$
– Wallace
Jan 14 at 22:39
$begingroup$
Sorry! I messed that up, In question one I believe the alternative = .05. I was under the impression that if you have a specific test case (such as the .05) that that was the alternative value
$endgroup$
– Brian
Jan 14 at 22:46
$begingroup$
$0.05$ and $0.01$ are the levels of significance of the tests but not the alternative hypotheses.
$endgroup$
– Henry
Jan 15 at 10:47
add a comment |
$begingroup$
Your formatting for this is incorrect, Null is not equal to 0.29, The correct way to state this is Null: p = 0.29, Also why are you saying alternative = 0.1? I can understand what you meant by the incorrect notation, but they are asking if the proportion is less than 29%, where did the 0.01 come from? Alternative should be p < 0.29 (Someone please correct me if I am wrong, It has been a while since I've done applied statistics)
$endgroup$
– Wallace
Jan 14 at 22:39
$begingroup$
Sorry! I messed that up, In question one I believe the alternative = .05. I was under the impression that if you have a specific test case (such as the .05) that that was the alternative value
$endgroup$
– Brian
Jan 14 at 22:46
$begingroup$
$0.05$ and $0.01$ are the levels of significance of the tests but not the alternative hypotheses.
$endgroup$
– Henry
Jan 15 at 10:47
$begingroup$
Your formatting for this is incorrect, Null is not equal to 0.29, The correct way to state this is Null: p = 0.29, Also why are you saying alternative = 0.1? I can understand what you meant by the incorrect notation, but they are asking if the proportion is less than 29%, where did the 0.01 come from? Alternative should be p < 0.29 (Someone please correct me if I am wrong, It has been a while since I've done applied statistics)
$endgroup$
– Wallace
Jan 14 at 22:39
$begingroup$
Your formatting for this is incorrect, Null is not equal to 0.29, The correct way to state this is Null: p = 0.29, Also why are you saying alternative = 0.1? I can understand what you meant by the incorrect notation, but they are asking if the proportion is less than 29%, where did the 0.01 come from? Alternative should be p < 0.29 (Someone please correct me if I am wrong, It has been a while since I've done applied statistics)
$endgroup$
– Wallace
Jan 14 at 22:39
$begingroup$
Sorry! I messed that up, In question one I believe the alternative = .05. I was under the impression that if you have a specific test case (such as the .05) that that was the alternative value
$endgroup$
– Brian
Jan 14 at 22:46
$begingroup$
Sorry! I messed that up, In question one I believe the alternative = .05. I was under the impression that if you have a specific test case (such as the .05) that that was the alternative value
$endgroup$
– Brian
Jan 14 at 22:46
$begingroup$
$0.05$ and $0.01$ are the levels of significance of the tests but not the alternative hypotheses.
$endgroup$
– Henry
Jan 15 at 10:47
$begingroup$
$0.05$ and $0.01$ are the levels of significance of the tests but not the alternative hypotheses.
$endgroup$
– Henry
Jan 15 at 10:47
add a comment |
1 Answer
1
active
oldest
votes
$begingroup$
Some hints to get you started:
For Question 1:
Event: For Company 1 rice production > 307200.0
$p = P(Event).$ Null hypothesis $H_0: p ge 0.29$ and
alternative hypothesis $H_a: p < 0.29.$ You may choose to test at the significance level $alpha = 0.05 = 5%,$ which will determine the critical value. I have no idea
where your got 0.01.
Note: The null hypothesis must always contain an $=$-sign in some way: perhaps $le, ge,$ or simply $=.$
For Question 2. $H_0: mu = 209500.0;$ alternative has $ne.$
answered Jan 15 at 2:17
BruceETBruceET
36.5k71540
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add a comment |
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1 Answer
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active
oldest
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1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
Some hints to get you started:
For Question 1:
Event: For Company 1 rice production > 307200.0
$p = P(Event).$ Null hypothesis $H_0: p ge 0.29$ and
alternative hypothesis $H_a: p < 0.29.$ You may choose to test at the significance level $alpha = 0.05 = 5%,$ which will determine the critical value. I have no idea
where your got 0.01.
Note: The null hypothesis must always contain an $=$-sign in some way: perhaps $le, ge,$ or simply $=.$
For Question 2. $H_0: mu = 209500.0;$ alternative has $ne.$
answered Jan 15 at 2:17
BruceETBruceET
36.5k71540
$endgroup$
add a comment |
$begingroup$
Some hints to get you started:
For Question 1:
Event: For Company 1 rice production > 307200.0
$p = P(Event).$ Null hypothesis $H_0: p ge 0.29$ and
alternative hypothesis $H_a: p < 0.29.$ You may choose to test at the significance level $alpha = 0.05 = 5%,$ which will determine the critical value. I have no idea
where your got 0.01.
Note: The null hypothesis must always contain an $=$-sign in some way: perhaps $le, ge,$ or simply $=.$
For Question 2. $H_0: mu = 209500.0;$ alternative has $ne.$
answered Jan 15 at 2:17
BruceETBruceET
36.5k71540
$endgroup$
add a comment |
$begingroup$
Some hints to get you started:
For Question 1:
Event: For Company 1 rice production > 307200.0
$p = P(Event).$ Null hypothesis $H_0: p ge 0.29$ and
alternative hypothesis $H_a: p < 0.29.$ You may choose to test at the significance level $alpha = 0.05 = 5%,$ which will determine the critical value. I have no idea
where your got 0.01.
Note: The null hypothesis must always contain an $=$-sign in some way: perhaps $le, ge,$ or simply $=.$
For Question 2. $H_0: mu = 209500.0;$ alternative has $ne.$
answered Jan 15 at 2:17
BruceETBruceET
36.5k71540
$endgroup$
Some hints to get you started:
For Question 1:
Event: For Company 1 rice production > 307200.0
$p = P(Event).$ Null hypothesis $H_0: p ge 0.29$ and
alternative hypothesis $H_a: p < 0.29.$ You may choose to test at the significance level $alpha = 0.05 = 5%,$ which will determine the critical value. I have no idea
where your got 0.01.
Note: The null hypothesis must always contain an $=$-sign in some way: perhaps $le, ge,$ or simply $=.$
For Question 2. $H_0: mu = 209500.0;$ alternative has $ne.$
answered Jan 15 at 2:17
BruceETBruceET
36.5k71540
answered Jan 15 at 2:17
BruceETBruceET
36.5k71540
answered Jan 15 at 2:17
BruceETBruceET
36.5k71540
answered Jan 15 at 2:17
BruceETBruceET
36.5k71540
36.5k71540
add a comment |
add a comment |
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$begingroup$
Your formatting for this is incorrect, Null is not equal to 0.29, The correct way to state this is Null: p = 0.29, Also why are you saying alternative = 0.1? I can understand what you meant by the incorrect notation, but they are asking if the proportion is less than 29%, where did the 0.01 come from? Alternative should be p < 0.29 (Someone please correct me if I am wrong, It has been a while since I've done applied statistics)
$endgroup$
– Wallace
Jan 14 at 22:39
$begingroup$
Sorry! I messed that up, In question one I believe the alternative = .05. I was under the impression that if you have a specific test case (such as the .05) that that was the alternative value
$endgroup$
– Brian
Jan 14 at 22:46
$begingroup$
$0.05$ and $0.01$ are the levels of significance of the tests but not the alternative hypotheses.
$endgroup$
– Henry
Jan 15 at 10:47