Ben is x cm tall. Kieran is 8cm taller than Ben. 2cm shorter than Ben. Write an expression, in terms of x....
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Ben is x cm tall. Kieran is 8cm taller than Ben. Bianca is 2cm shorter than Ben. Write an expression, in terms of x, for the mean of their heights in centimetres. Give your answer in simplest form.
Please Can anyone help me to answer this question.
linear-algebra
asked Dec 2 at 20:17
Rinta
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closed as off-topic by Peter Franek, KReiser, Leucippus, amWhy, Shailesh Dec 3 at 0:12
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – Peter Franek, KReiser, Leucippus, amWhy, Shailesh
If this question can be reworded to fit the rules in the help center, please edit the question.
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Ben is x cm tall. Kieran is 8cm taller than Ben. Bianca is 2cm shorter than Ben. Write an expression, in terms of x, for the mean of their heights in centimetres. Give your answer in simplest form.
Please Can anyone help me to answer this question.
linear-algebra
asked Dec 2 at 20:17
Rinta
1
New contributor
Rinta is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
closed as off-topic by Peter Franek, KReiser, Leucippus, amWhy, Shailesh Dec 3 at 0:12
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – Peter Franek, KReiser, Leucippus, amWhy, Shailesh
If this question can be reworded to fit the rules in the help center, please edit the question.
4
Welcome to MSE, Rinta. This is a platform for discussing math problems, not for solving someone else's homework. If you need help, it is expected that you share more context and your own attempts to find the solution / where you are stack / etc.
– Peter Franek
Dec 2 at 20:21
To expand on Peter's suggestion, work out each person's height in centimetres, and the sum of those heights, and the mean of those heights. Edit into the question whatever you manage, plus a "then I get stuck" comment.
– J.G.
Dec 2 at 20:24
add a comment |
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up vote
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down vote
favorite
Ben is x cm tall. Kieran is 8cm taller than Ben. Bianca is 2cm shorter than Ben. Write an expression, in terms of x, for the mean of their heights in centimetres. Give your answer in simplest form.
Please Can anyone help me to answer this question.
linear-algebra
asked Dec 2 at 20:17
Rinta
1
New contributor
Rinta is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Ben is x cm tall. Kieran is 8cm taller than Ben. Bianca is 2cm shorter than Ben. Write an expression, in terms of x, for the mean of their heights in centimetres. Give your answer in simplest form.
Please Can anyone help me to answer this question.
linear-algebra
linear-algebra
asked Dec 2 at 20:17
Rinta
1
New contributor
Rinta is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked Dec 2 at 20:17
Rinta
1
New contributor
Rinta is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked Dec 2 at 20:17
Rinta
1
New contributor
Rinta is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked Dec 2 at 20:17
Rinta
1
asked Dec 2 at 20:17
Rinta
1
1
New contributor
Rinta is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Rinta is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Rinta is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
closed as off-topic by Peter Franek, KReiser, Leucippus, amWhy, Shailesh Dec 3 at 0:12
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – Peter Franek, KReiser, Leucippus, amWhy, Shailesh
If this question can be reworded to fit the rules in the help center, please edit the question.
closed as off-topic by Peter Franek, KReiser, Leucippus, amWhy, Shailesh Dec 3 at 0:12
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – Peter Franek, KReiser, Leucippus, amWhy, Shailesh
If this question can be reworded to fit the rules in the help center, please edit the question.
4
Welcome to MSE, Rinta. This is a platform for discussing math problems, not for solving someone else's homework. If you need help, it is expected that you share more context and your own attempts to find the solution / where you are stack / etc.
– Peter Franek
Dec 2 at 20:21
To expand on Peter's suggestion, work out each person's height in centimetres, and the sum of those heights, and the mean of those heights. Edit into the question whatever you manage, plus a "then I get stuck" comment.
– J.G.
Dec 2 at 20:24
add a comment |
4
Welcome to MSE, Rinta. This is a platform for discussing math problems, not for solving someone else's homework. If you need help, it is expected that you share more context and your own attempts to find the solution / where you are stack / etc.
– Peter Franek
Dec 2 at 20:21
To expand on Peter's suggestion, work out each person's height in centimetres, and the sum of those heights, and the mean of those heights. Edit into the question whatever you manage, plus a "then I get stuck" comment.
– J.G.
Dec 2 at 20:24
4
4
Welcome to MSE, Rinta. This is a platform for discussing math problems, not for solving someone else's homework. If you need help, it is expected that you share more context and your own attempts to find the solution / where you are stack / etc.
– Peter Franek
Dec 2 at 20:21
Welcome to MSE, Rinta. This is a platform for discussing math problems, not for solving someone else's homework. If you need help, it is expected that you share more context and your own attempts to find the solution / where you are stack / etc.
– Peter Franek
Dec 2 at 20:21
To expand on Peter's suggestion, work out each person's height in centimetres, and the sum of those heights, and the mean of those heights. Edit into the question whatever you manage, plus a "then I get stuck" comment.
– J.G.
Dec 2 at 20:24
To expand on Peter's suggestion, work out each person's height in centimetres, and the sum of those heights, and the mean of those heights. Edit into the question whatever you manage, plus a "then I get stuck" comment.
– J.G.
Dec 2 at 20:24
add a comment |
1 Answer
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Hint: Let $K$ be the height of Kieran and $B$ the height of Bianca. The mean height is simply $$frac{K+B+x}{3}$$ i.e. just add up the heights and divide by the number of people. Now how do you write $K$ and $B$ in terms of $x$, Ben's height?
answered Dec 2 at 20:23
Dave
8,63611033
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
0
down vote
Hint: Let $K$ be the height of Kieran and $B$ the height of Bianca. The mean height is simply $$frac{K+B+x}{3}$$ i.e. just add up the heights and divide by the number of people. Now how do you write $K$ and $B$ in terms of $x$, Ben's height?
answered Dec 2 at 20:23
Dave
8,63611033
add a comment |
up vote
0
down vote
Hint: Let $K$ be the height of Kieran and $B$ the height of Bianca. The mean height is simply $$frac{K+B+x}{3}$$ i.e. just add up the heights and divide by the number of people. Now how do you write $K$ and $B$ in terms of $x$, Ben's height?
answered Dec 2 at 20:23
Dave
8,63611033
add a comment |
up vote
0
down vote
up vote
0
down vote
Hint: Let $K$ be the height of Kieran and $B$ the height of Bianca. The mean height is simply $$frac{K+B+x}{3}$$ i.e. just add up the heights and divide by the number of people. Now how do you write $K$ and $B$ in terms of $x$, Ben's height?
answered Dec 2 at 20:23
Dave
8,63611033
Hint: Let $K$ be the height of Kieran and $B$ the height of Bianca. The mean height is simply $$frac{K+B+x}{3}$$ i.e. just add up the heights and divide by the number of people. Now how do you write $K$ and $B$ in terms of $x$, Ben's height?
answered Dec 2 at 20:23
Dave
8,63611033
answered Dec 2 at 20:23
Dave
8,63611033
answered Dec 2 at 20:23
Dave
8,63611033
answered Dec 2 at 20:23
Dave
8,63611033
8,63611033
add a comment |
add a comment |
4
Welcome to MSE, Rinta. This is a platform for discussing math problems, not for solving someone else's homework. If you need help, it is expected that you share more context and your own attempts to find the solution / where you are stack / etc.
– Peter Franek
Dec 2 at 20:21
To expand on Peter's suggestion, work out each person's height in centimetres, and the sum of those heights, and the mean of those heights. Edit into the question whatever you manage, plus a "then I get stuck" comment.
– J.G.
Dec 2 at 20:24