Derivative of implicit function defined by $y^3 + tan(xy) = 8$ [closed]
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Given the equation $y^3 + tan(xy) = 8$, find $dy/dx$ without using $y'=-F_x/F_y$.
calculus derivatives
closed as off-topic by Randall, darij grinberg, KReiser, RRL, user302797 Dec 3 at 1:06
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Given the equation $y^3 + tan(xy) = 8$, find $dy/dx$ without using $y'=-F_x/F_y$.
calculus derivatives
closed as off-topic by Randall, darij grinberg, KReiser, RRL, user302797 Dec 3 at 1:06
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – Randall, darij grinberg, KReiser, RRL, user302797
If this question can be reworded to fit the rules in the help center, please edit the question.
Implicit differentiation...?
– Andrew Li
Dec 2 at 19:50
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up vote
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Given the equation $y^3 + tan(xy) = 8$, find $dy/dx$ without using $y'=-F_x/F_y$.
calculus derivatives
Given the equation $y^3 + tan(xy) = 8$, find $dy/dx$ without using $y'=-F_x/F_y$.
calculus derivatives
calculus derivatives
edited Dec 2 at 20:43
rafa11111
1,023417
1,023417
asked Dec 2 at 19:39
M.s
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closed as off-topic by Randall, darij grinberg, KReiser, RRL, user302797 Dec 3 at 1:06
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – Randall, darij grinberg, KReiser, RRL, user302797
If this question can be reworded to fit the rules in the help center, please edit the question.
closed as off-topic by Randall, darij grinberg, KReiser, RRL, user302797 Dec 3 at 1:06
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – Randall, darij grinberg, KReiser, RRL, user302797
If this question can be reworded to fit the rules in the help center, please edit the question.
Implicit differentiation...?
– Andrew Li
Dec 2 at 19:50
add a comment |
Implicit differentiation...?
– Andrew Li
Dec 2 at 19:50
Implicit differentiation...?
– Andrew Li
Dec 2 at 19:50
Implicit differentiation...?
– Andrew Li
Dec 2 at 19:50
add a comment |
1 Answer
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By the method of implicit differentiation (using the chain rule), we have $$3y^2frac{dy}{dx}+sec^2(xy)left(y+xfrac{dy}{dx}right)=0$$ Now simplify and solve for $frac{dy}{dx}$.
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1 Answer
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1 Answer
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By the method of implicit differentiation (using the chain rule), we have $$3y^2frac{dy}{dx}+sec^2(xy)left(y+xfrac{dy}{dx}right)=0$$ Now simplify and solve for $frac{dy}{dx}$.
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By the method of implicit differentiation (using the chain rule), we have $$3y^2frac{dy}{dx}+sec^2(xy)left(y+xfrac{dy}{dx}right)=0$$ Now simplify and solve for $frac{dy}{dx}$.
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By the method of implicit differentiation (using the chain rule), we have $$3y^2frac{dy}{dx}+sec^2(xy)left(y+xfrac{dy}{dx}right)=0$$ Now simplify and solve for $frac{dy}{dx}$.
By the method of implicit differentiation (using the chain rule), we have $$3y^2frac{dy}{dx}+sec^2(xy)left(y+xfrac{dy}{dx}right)=0$$ Now simplify and solve for $frac{dy}{dx}$.
answered Dec 2 at 20:13
Dave
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Implicit differentiation...?
– Andrew Li
Dec 2 at 19:50