Can composition of morphisms in a category be carried out on any subgraph of a commutative diagram, in-place?
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Here is what the rule looks like to us and how we specify it to the app I'm writing.
I was wondering can you take any commutative diagram $J$ and apply this rule to a subgraph matching $A xrightarrow{a} B xrightarrow{b} C$ in place, all the while leaving another commutative diagram. Or does adding in the hypotenuse sometimes break commutativity of a larger diagram?
If it preserves commutativity, what is a simple proof?
category-theory math-software function-and-relation-composition natural-deduction diagram-chasing
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up vote
0
down vote
favorite
Here is what the rule looks like to us and how we specify it to the app I'm writing.
I was wondering can you take any commutative diagram $J$ and apply this rule to a subgraph matching $A xrightarrow{a} B xrightarrow{b} C$ in place, all the while leaving another commutative diagram. Or does adding in the hypotenuse sometimes break commutativity of a larger diagram?
If it preserves commutativity, what is a simple proof?
category-theory math-software function-and-relation-composition natural-deduction diagram-chasing
add a comment |
up vote
0
down vote
favorite
up vote
0
down vote
favorite
Here is what the rule looks like to us and how we specify it to the app I'm writing.
I was wondering can you take any commutative diagram $J$ and apply this rule to a subgraph matching $A xrightarrow{a} B xrightarrow{b} C$ in place, all the while leaving another commutative diagram. Or does adding in the hypotenuse sometimes break commutativity of a larger diagram?
If it preserves commutativity, what is a simple proof?
category-theory math-software function-and-relation-composition natural-deduction diagram-chasing
Here is what the rule looks like to us and how we specify it to the app I'm writing.
I was wondering can you take any commutative diagram $J$ and apply this rule to a subgraph matching $A xrightarrow{a} B xrightarrow{b} C$ in place, all the while leaving another commutative diagram. Or does adding in the hypotenuse sometimes break commutativity of a larger diagram?
If it preserves commutativity, what is a simple proof?
category-theory math-software function-and-relation-composition natural-deduction diagram-chasing
category-theory math-software function-and-relation-composition natural-deduction diagram-chasing
asked Dec 1 at 11:33
Roll up and smoke Adjoint
8,96252357
8,96252357
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1 Answer
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up vote
2
down vote
accepted
Consider any two parallel paths.
Change every occurance of the new arrow $bcirc a$ to the subpath $a, b$.
Since the original diagram commutes, the composition of the two changed paths coincide.
Consequently, the new diagram is commutative, as well.
add a comment |
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
2
down vote
accepted
Consider any two parallel paths.
Change every occurance of the new arrow $bcirc a$ to the subpath $a, b$.
Since the original diagram commutes, the composition of the two changed paths coincide.
Consequently, the new diagram is commutative, as well.
add a comment |
up vote
2
down vote
accepted
Consider any two parallel paths.
Change every occurance of the new arrow $bcirc a$ to the subpath $a, b$.
Since the original diagram commutes, the composition of the two changed paths coincide.
Consequently, the new diagram is commutative, as well.
add a comment |
up vote
2
down vote
accepted
up vote
2
down vote
accepted
Consider any two parallel paths.
Change every occurance of the new arrow $bcirc a$ to the subpath $a, b$.
Since the original diagram commutes, the composition of the two changed paths coincide.
Consequently, the new diagram is commutative, as well.
Consider any two parallel paths.
Change every occurance of the new arrow $bcirc a$ to the subpath $a, b$.
Since the original diagram commutes, the composition of the two changed paths coincide.
Consequently, the new diagram is commutative, as well.
answered Dec 1 at 14:16
Berci
59.2k23671
59.2k23671
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