T/F: If X is any random variable, E(X^3 +1) = (E(X))^3 +1 [closed]
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T/F: If X is any random variable, E(X^3 +1) = (E(X))^3 +1
I'm inclined to say that it's true after a couple of trial & errors with normal random variables, but I'm unsure exactly why !
statistics expected-value
asked Dec 2 at 20:36
kmediate
115
closed as off-topic by amWhy, NCh, Leucippus, Cesareo, John B Dec 3 at 11:17
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – amWhy, NCh, Leucippus, Cesareo, John B
If this question can be reworded to fit the rules in the help center, please edit the question.
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T/F: If X is any random variable, E(X^3 +1) = (E(X))^3 +1
I'm inclined to say that it's true after a couple of trial & errors with normal random variables, but I'm unsure exactly why !
statistics expected-value
asked Dec 2 at 20:36
kmediate
115
closed as off-topic by amWhy, NCh, Leucippus, Cesareo, John B Dec 3 at 11:17
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – amWhy, NCh, Leucippus, Cesareo, John B
If this question can be reworded to fit the rules in the help center, please edit the question.
1
False. Try harder with normal variables. Or try something else: the statement is very far from being true, so you'll succeed with almost everything.
– zhoraster
Dec 2 at 20:40
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up vote
0
down vote
favorite
T/F: If X is any random variable, E(X^3 +1) = (E(X))^3 +1
I'm inclined to say that it's true after a couple of trial & errors with normal random variables, but I'm unsure exactly why !
statistics expected-value
asked Dec 2 at 20:36
kmediate
115
T/F: If X is any random variable, E(X^3 +1) = (E(X))^3 +1
I'm inclined to say that it's true after a couple of trial & errors with normal random variables, but I'm unsure exactly why !
statistics expected-value
statistics expected-value
asked Dec 2 at 20:36
kmediate
115
asked Dec 2 at 20:36
kmediate
115
asked Dec 2 at 20:36
kmediate
115
asked Dec 2 at 20:36
kmediate
115
asked Dec 2 at 20:36
kmediate
115
115
closed as off-topic by amWhy, NCh, Leucippus, Cesareo, John B Dec 3 at 11:17
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – amWhy, NCh, Leucippus, Cesareo, John B
If this question can be reworded to fit the rules in the help center, please edit the question.
closed as off-topic by amWhy, NCh, Leucippus, Cesareo, John B Dec 3 at 11:17
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – amWhy, NCh, Leucippus, Cesareo, John B
If this question can be reworded to fit the rules in the help center, please edit the question.
1
False. Try harder with normal variables. Or try something else: the statement is very far from being true, so you'll succeed with almost everything.
– zhoraster
Dec 2 at 20:40
add a comment |
1
False. Try harder with normal variables. Or try something else: the statement is very far from being true, so you'll succeed with almost everything.
– zhoraster
Dec 2 at 20:40
1
1
False. Try harder with normal variables. Or try something else: the statement is very far from being true, so you'll succeed with almost everything.
– zhoraster
Dec 2 at 20:40
False. Try harder with normal variables. Or try something else: the statement is very far from being true, so you'll succeed with almost everything.
– zhoraster
Dec 2 at 20:40
add a comment |
1 Answer
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Here is a counter example. Let $Xsim U(0,1)$ therefore $$E(X^3+1)=int_{0}^{1}x^3+1dx={5over 4}$$and $$[E(X)]^3+1=left[int_{0}^{1}xdxright]^3+1={9over 8}$$clearly$$E(X^3+1)ne [E(X)]^3+1$$
answered Dec 2 at 20:50
Mostafa Ayaz
13.4k3836
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
1
down vote
Here is a counter example. Let $Xsim U(0,1)$ therefore $$E(X^3+1)=int_{0}^{1}x^3+1dx={5over 4}$$and $$[E(X)]^3+1=left[int_{0}^{1}xdxright]^3+1={9over 8}$$clearly$$E(X^3+1)ne [E(X)]^3+1$$
answered Dec 2 at 20:50
Mostafa Ayaz
13.4k3836
add a comment |
up vote
1
down vote
Here is a counter example. Let $Xsim U(0,1)$ therefore $$E(X^3+1)=int_{0}^{1}x^3+1dx={5over 4}$$and $$[E(X)]^3+1=left[int_{0}^{1}xdxright]^3+1={9over 8}$$clearly$$E(X^3+1)ne [E(X)]^3+1$$
answered Dec 2 at 20:50
Mostafa Ayaz
13.4k3836
add a comment |
up vote
1
down vote
up vote
1
down vote
Here is a counter example. Let $Xsim U(0,1)$ therefore $$E(X^3+1)=int_{0}^{1}x^3+1dx={5over 4}$$and $$[E(X)]^3+1=left[int_{0}^{1}xdxright]^3+1={9over 8}$$clearly$$E(X^3+1)ne [E(X)]^3+1$$
answered Dec 2 at 20:50
Mostafa Ayaz
13.4k3836
Here is a counter example. Let $Xsim U(0,1)$ therefore $$E(X^3+1)=int_{0}^{1}x^3+1dx={5over 4}$$and $$[E(X)]^3+1=left[int_{0}^{1}xdxright]^3+1={9over 8}$$clearly$$E(X^3+1)ne [E(X)]^3+1$$
answered Dec 2 at 20:50
Mostafa Ayaz
13.4k3836
answered Dec 2 at 20:50
Mostafa Ayaz
13.4k3836
answered Dec 2 at 20:50
Mostafa Ayaz
13.4k3836
answered Dec 2 at 20:50
Mostafa Ayaz
13.4k3836
13.4k3836
add a comment |
add a comment |
1
False. Try harder with normal variables. Or try something else: the statement is very far from being true, so you'll succeed with almost everything.
– zhoraster
Dec 2 at 20:40