ODE numerical method that produces a region containing the integral curve












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Are there numerical methods for ODEs that are capable of producing regions (linearly bounded or otherwise) that definitely contain a portion of a specified integral curve?



I'm wondering if there are numerical methods for solving ODEs that are roughly analogous to interval arithmetic for real-valued functions.



Suppose we have two unknowns $y(x)$ and $x$ where $y' = F(x, y)$. Suppose that $(x_0, y_0)$ is our initial value and suppose that $-1 le x le 1$ is the range of values of $x$ that we're interested in. In other words, $(x_0, y_0)$ is how we pick out a particular integral curve and $S stackrel{text{def}}{=} left{ (x,y) : x, y in mathbb{R} land -1 le x le 1 right}$ is the region of the $xy$ plane that we want to pick a subset of.



Are there any methods that produce a subset of $S$ that the integral curve passing through $(x_0, y_0)$ must reside in that is smaller than $S$ itself, preferably one where the area covered by the estimate region can be made arbitrarily small by picking a step size or something similar?










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    $begingroup$
    Definitely yes (and based on interval arithmetic), although it's a somewhat tricky problem. Try searching for "validated numerics ODE".
    $endgroup$
    – Hans Lundmark
    Jan 8 at 9:01
















1












$begingroup$


Are there numerical methods for ODEs that are capable of producing regions (linearly bounded or otherwise) that definitely contain a portion of a specified integral curve?



I'm wondering if there are numerical methods for solving ODEs that are roughly analogous to interval arithmetic for real-valued functions.



Suppose we have two unknowns $y(x)$ and $x$ where $y' = F(x, y)$. Suppose that $(x_0, y_0)$ is our initial value and suppose that $-1 le x le 1$ is the range of values of $x$ that we're interested in. In other words, $(x_0, y_0)$ is how we pick out a particular integral curve and $S stackrel{text{def}}{=} left{ (x,y) : x, y in mathbb{R} land -1 le x le 1 right}$ is the region of the $xy$ plane that we want to pick a subset of.



Are there any methods that produce a subset of $S$ that the integral curve passing through $(x_0, y_0)$ must reside in that is smaller than $S$ itself, preferably one where the area covered by the estimate region can be made arbitrarily small by picking a step size or something similar?










share|cite|improve this question











$endgroup$








  • 1




    $begingroup$
    Definitely yes (and based on interval arithmetic), although it's a somewhat tricky problem. Try searching for "validated numerics ODE".
    $endgroup$
    – Hans Lundmark
    Jan 8 at 9:01














1












1








1





$begingroup$


Are there numerical methods for ODEs that are capable of producing regions (linearly bounded or otherwise) that definitely contain a portion of a specified integral curve?



I'm wondering if there are numerical methods for solving ODEs that are roughly analogous to interval arithmetic for real-valued functions.



Suppose we have two unknowns $y(x)$ and $x$ where $y' = F(x, y)$. Suppose that $(x_0, y_0)$ is our initial value and suppose that $-1 le x le 1$ is the range of values of $x$ that we're interested in. In other words, $(x_0, y_0)$ is how we pick out a particular integral curve and $S stackrel{text{def}}{=} left{ (x,y) : x, y in mathbb{R} land -1 le x le 1 right}$ is the region of the $xy$ plane that we want to pick a subset of.



Are there any methods that produce a subset of $S$ that the integral curve passing through $(x_0, y_0)$ must reside in that is smaller than $S$ itself, preferably one where the area covered by the estimate region can be made arbitrarily small by picking a step size or something similar?










share|cite|improve this question











$endgroup$




Are there numerical methods for ODEs that are capable of producing regions (linearly bounded or otherwise) that definitely contain a portion of a specified integral curve?



I'm wondering if there are numerical methods for solving ODEs that are roughly analogous to interval arithmetic for real-valued functions.



Suppose we have two unknowns $y(x)$ and $x$ where $y' = F(x, y)$. Suppose that $(x_0, y_0)$ is our initial value and suppose that $-1 le x le 1$ is the range of values of $x$ that we're interested in. In other words, $(x_0, y_0)$ is how we pick out a particular integral curve and $S stackrel{text{def}}{=} left{ (x,y) : x, y in mathbb{R} land -1 le x le 1 right}$ is the region of the $xy$ plane that we want to pick a subset of.



Are there any methods that produce a subset of $S$ that the integral curve passing through $(x_0, y_0)$ must reside in that is smaller than $S$ itself, preferably one where the area covered by the estimate region can be made arbitrarily small by picking a step size or something similar?







ordinary-differential-equations numerical-methods






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share|cite|improve this question













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edited Jan 8 at 9:05







Gregory Nisbet

















asked Jan 8 at 8:11









Gregory NisbetGregory Nisbet

756612




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  • 1




    $begingroup$
    Definitely yes (and based on interval arithmetic), although it's a somewhat tricky problem. Try searching for "validated numerics ODE".
    $endgroup$
    – Hans Lundmark
    Jan 8 at 9:01














  • 1




    $begingroup$
    Definitely yes (and based on interval arithmetic), although it's a somewhat tricky problem. Try searching for "validated numerics ODE".
    $endgroup$
    – Hans Lundmark
    Jan 8 at 9:01








1




1




$begingroup$
Definitely yes (and based on interval arithmetic), although it's a somewhat tricky problem. Try searching for "validated numerics ODE".
$endgroup$
– Hans Lundmark
Jan 8 at 9:01




$begingroup$
Definitely yes (and based on interval arithmetic), although it's a somewhat tricky problem. Try searching for "validated numerics ODE".
$endgroup$
– Hans Lundmark
Jan 8 at 9:01










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